A bowl contains 7 red balls and 10 blue balls. A woman selects 4 balls at random from the bowl. How many different selections ar

Question

3 years ago

10

e possible if at least 3 balls must be blue?

1 answer:

denis-greek [22] · Answer 1 · 2022-08-08T20:49:33+03:00

Answer:

1050 possible selections

Explanation:

Number of red balls = 7

Number of blue balls = 10

Let blue balls be B and red balls be R

four balls are to be selected. At least three must be blue.

the first combination is 4blue 0red

second combination is 3blue 1red

(10C4*7C0 + 10C3*7C1)

210 *1 +120 *7

210+840

=1050 possibilities