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Ksenya-84 [330]
2 years ago
15

If a mineral sample contains 25.6 g of Scandium, how many atoms of Scandium are in the

Chemistry
1 answer:
lapo4ka [179]2 years ago
5 0

Answer:

A. 0.569

Explanation:

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The pK of acetic acid is pK = 4.76. For a 0.1 M solution of acetic acid at a pH = 4.76 what is the concentration of [H+]?
spin [16.1K]

Answer:

[H+] = 1.74 x 10⁻⁵

Explanation:

By definition pH = -log  [H+]

Therefore, given the pH,  all we have to do is  solve algebraically for  [H+] :

[H+]  = antilog ( -pH ) =  10^-4.76 = 1.74 x 10⁻⁵

6 0
3 years ago
rank the following list of aqueous solutions and solvents according to decreasing vapor pressure the substance with the higher v
Tpy6a [65]

Answer: 0.050M urea, 0.10M glucose, 0.2M sucrose, pure water

Explanation:

Vapor pressure refers to the ease with which a liquid substance is transformed into vapour. High vapour density implies that the liquid is easily transformed into gas. Pure water is expected to have the lowest vapour density since it is held by strong intermolecular forces in the liquid state. Urea is an organic liquid held by weak Van der Waals forces hence its extremely high vapor pressure.

8 0
3 years ago
What is the combustibility of calcium?
Alexeev081 [22]

the combustibility of calcium is relitivly high



3 0
3 years ago
Read 2 more answers
Which of these is an example of heat transferred by radiation?
timofeeve [1]
A I think I’m not sure
5 0
3 years ago
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How much heat is required to vaporize 31.5 gg of acetone (C3H6O)(C3H6O) at 25 ∘C∘C? The heat of vaporization for acetone at this
KiRa [710]

Answer:

≅ 16.81 kJ

Explanation:

Given that;

mass of acetone = 31.5 g

molar mass of acetone = 58.08 g/mol

heat of vaporization for acetone = 31.0 kJ/molkJ/mol.

Number of moles = \frac{mass}{molar mass}

Number of moles of acetone = \frac{31.5}{58.08}

Number of moles  of acetone = 0.5424 mole

The heat required to vaporize 31.5 g of acetone can be determined by multiplying the number of moles of acetone with the heat of vaporization of acetone;

Hence;

The heat required to vaporize 31.5 g of acetone = 0.5424 mole × 31.0 kJ/mol

The heat required to vaporize 31.5 g of acetone = 16.8144 kJ

≅ 16.81 kJ

4 0
3 years ago
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