The velocity of the bullet and the block just after impact is mathematically given as
u=6.647m/s
v=1.534m/s
<h3> Velocity of the bullet and the block</h3>Question Parameters:
In the ballistic pendulum experiment, a bullet of mass 0.06 kg is fired
horizontally into a wooden block of mass 0.2 kg.
the block is 0.12 m above its initial position.
Generally the equation for the conservation of energy is mathematically given as
0.5(m+n)v^2=(m+n)gh
Therefore
v^2=2gh
v=1.534m/s
Hence
mu+m*0=(m+n)v
0.060*u=(0.060+0.2)*1.534
u=6.647m/s
For more information on mass
Answer:
H = 6.93 m
Explanation:
given data
velocity v = 35 m/s
horizontal component Vx = 33 m/s
solution
we get here maximum height so first we get vertical component here that is express as
Vy = .........................1
put here value
Vy =
Vy = 11.66 m/s
and
now we get height
H = .............................2
put here value
H =
H = 6.93 m
Answer:
<h2>15.25 N</h2>Explanation:
A force of is acting on a wagon along the road. The wagon weights
. Acceleration of the wagon is given as
.
Consider the block as the system, the forces acting are Frictional force, Gravitational force, Normal reaction and External force applied by us.
Gravitational Force and Normal Reaction cancel out each other.
Net External Force = Mass of system/wagon Acceleration of wagon
has a negative sign because it opposes the motion of the wagon.
∴ Frictional Force = 15.25 N