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Readme [11.4K]
3 years ago
14

24. Compare and contrast the 'Big Bang Theory' with the 'Creation Model for the origin of the

Physics
1 answer:
pishuonlain [190]3 years ago
5 0
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A wire carrying an electric current is often likened to a pipe carrying water. What part of this analogy is incorrect?
tamaranim1 [39]

In a direct current (DC) electrical circuit, the voltage (V in volts) is an expression of the available energy per unit charge which drives the electric current (I in amperes) around a closed circuit. Increasing the resistance (R in ohms) will proportionately decrease the current which may be driven through the circuit by the voltage.

Each quantity and each operational relationship in a battery-operated DC circuit has a direct analog in the water circuit. The nature of the analogies can help develop an understanding of the quantities in basic electric ciruits. In the water circuit, the pressure P drives the water around the closed loop of pipe at a certain volume flow rate F. If the resistance to flow R is increased, then the volume flow rate decreases proportionately. You may click any component or any relationship to explore the the details of the analogy with a DC electric circuit.

6 0
4 years ago
A 20 cm long spring is attached to a wall. The spring stretches to a length of 22 cm when you pull on it with a force of 100 n.
kenny6666 [7]

Answer:

5000 N/m

Explanation:

Hooke's law for the spring is

F = k \Delta x

where here we have

F = 100 N is the force applied to the spring

k is the spring constant

\Delta x = 22 cm - 20 cm = 2 cm = 0.02 m is the stretching of the spring with respect to its equilibrium position

Solving the equation for k, we find the spring constant:

k=\frac{F}{\Delta x}=\frac{100 N}{0.02 m}=5000 N/m

8 0
4 years ago
Why are denser materials found closer to earths center
ICE Princess25 [194]
Denser materials tend to be closer to earths center due to their mass gravity is shown by the equation mg
Which stands for mass x gravity.
5 0
3 years ago
A 500 kg car is at rest at the top of a 72 m high hill. The car rolls to the bottom of the hill. At the bottom of the hill, the
rjkz [21]

Explanation: Solution

1.

Gravitational potential energy

U=mgh=500*9.8*50

U=245000 J

2.

Kinetic energy is present at bottom of the hill

K=(1/2)mV2=(1/2)*500*27.82

K=193210 J

3.

Work done by friction

W=193210-245000=-51790 J

3 0
3 years ago
A rocket is launched with a velocity of 30 m/s at 40° to the horizontal. How far will it travel horizontally? 0 3.01 m 0 90.54 m
Lapatulllka [165]

Answer:

The horizontal distance traveled by the rocket is 90.46 m

Explanation:

Given;

initial velocity of the rocket, u = 30 m/s

angle of projection, θ = 40°

the horizontal distance traveled by the rocket = ?

The horizontal distance traveled by the rocket is given by the range of the projectile.

The range of the projectile is given as;

R = \frac{u^2Sin(2\theta)}{g}\\\\R = \frac{(30)^2sin(80^0)}{9.8}\\\\R = 90.46 \ m

Therefore, the horizontal distance traveled by the rocket is 90.46 m

The closest answer in the given options is 90.54 m

3 0
3 years ago
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