Radio waves infrared rays, visible light, ultraviolet rays, X-rays, and gamma rays are all types of electromagnetic radiation. Radio waves have the longest wavelength, and gamma rays have the shortest wavelength.
Answer:
See explanation
Explanation:
I believe that the aim of the scientist is to determine the effect of a cancer drug on mice with lymphoma. In this experiment, the mice with lymphoma are exposed to the drug. This is the treatment in the experiment. A control group of mice having lymphoma is not exposed to this treatment, this is the control group. This control group establishes a baseline for the study.
By comparing the outcome of the experimental and control groups, the effect of a cancer drug on mice with lymphoma can be determined.
OP already did it - CONGRATS!!
here are the steps 2 get the same ans:
(NH4)2 CO3 has 2x N, 8x H, 1x C and 3x O per molecule
so its molecular mass = 2x14 + 8x1 + 1x12 + 3x16
=28+8+12+48
=96g
of that 96g, 8x1=8g is due to Hydrogen
so by ratio n proportion, 1.00g will have 1x8/96 = 1/12g = 0.083g of H
Answer:
B
Explanation:
A chemical reaction equation is balanced if the number of atoms of each element on the right hand side of the reaction equation is the same as the number of atoms of the same element on the left hand side of the reaction equation.
By inspection, the chemical reaction written in the question is a balanced chemical reaction equation.
However, the statement in option B that more molecules of N2 are needed to produce NH3 than molecules of H2 is a false statement since only one mole of N2 and three moles of H2 are required to produce NH3 according to the reaction equation as written in the question.
In order to calculate the number of atoms present in 0.53 grams of P₂O₅, first calculate the number of moles for given mass.
As, Moles is given as,
Moles = Mass / M.mass
Moles = 0.53 g ÷ 283.88 g.mol⁻¹
Moles = 0.00186 moles
Now calculate the number of Molecules present in calculated moles of P₂O₅.
As,
1 Mole of P₂O₅ contains = 6.022 × 10²³ Molecules
So,
0.00186 Moles of P₂O₅ contain = X Molecules
Solving for X,
X = (0.00186 mol × 6.022 × 10²³ Molecules) ÷ 1 mol
X = 1.12 × 10²¹ Molecules
Also, in P₂O₅ there are 7 atoms, in 1.12 × 10²¹ Molecules there will be.....
= 1.12 × 10²¹ × 7
= 7.84 × 10²¹ Atoms
Result:
7.84 × 10²¹ Atoms are present in 0.53 grams of P₂O₅.