Using the Equation:
v² = vi² + 2 · a · s → Eq.1
where,
v = final velocity
vi = initial velocity
a = acceleration
s = distance
<span><span>We know that vi = 0 because the ball was at rest initially.
</span><span>
Therefore,
Solving Eq.1 for acceleration,
</span></span> v² = vi² + 2 · a · s
v² = 0 + 2 · a · s
v² = 2 · a · s
Rearranging for a,
a = v ²/2·<span>s
Substituting the values,
a = 46</span>²/2×1<span>
a = 1058 m/s</span>²
<span>Now applying Newton's 2nd law of motion,
</span>
<span>F = ma
= 0.145</span>×<span>1058
F = 153.4 N</span>
Answer:
Resistance = 252.53 Ohms
Explanation:
Given the following data;
Charge = 0.125 C
Voltage = 5 V
Time = 6.3 seconds
To find the resistance;
First of all, we would determine the current flowing through the battery;
Quantity of charge, Q = current * time
0.125 = current * 6.3
Current = 0.125/6.3
Current = 0.0198 A
Next, we find the resistance;
Resistance = voltage/current
Resistance = 5/0.0198
Resistance = 252.53 Ohms
Answer:
1.97 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.8 m/s²
Solving the above equation we get
So, the time the package was in the air is 1.97 seconds
Answer:
if I am correct, they indicate less steep terrain. think of it as the steeper the terrain the closer together the lines would be. hope that makes sense for you guys.
