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Alisiya [41]
3 years ago
14

How are Fahrenheit temperatures converted to Celsius temperature

Physics
2 answers:
prohojiy [21]3 years ago
5 0

Answer:

hope it helps

Explanation:

C°=(F°-32)×5/9 is the formula of converting

katrin2010 [14]3 years ago
3 0
Start with the temperature in Fahrenheit (e.g., 100 degrees). Subtract 32 from this figure (e.g., 100 - 32 = 68). Divide your answer by 1.8 (e.g., 68 / 1.8 = 37.78)
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A gardener mows a lawn with an old-fashioned push mower. The handle of the mower makes an angle of 320 with the surface of the l
Virty [35]

Answer:

N = 337.96 N

Explanation:

∅ = 32º

F = 249 N

m = 21 Kg

N = ?

We can apply:

∑ F = 0  (↑)

- Fy - W + N = 0   ⇒    N = Fy + W

⇒  F*Sin ∅ + m*g = N

⇒  N = (249 N*Sin32º) + (21 Kg*9.81 m/s²)

⇒  N = 337.96 N  (↑)

8 0
3 years ago
A circular radar antenna on a Coast Guard ship has a diameter of 2.10 m and radiates at a frequency of 16.0 GHz. Two small boats
Anna35 [415]

Answer:

d = 76.5 m

Explanation:

To find the distance at which the boats will be detected as two objects, we need to use the following equation:

\theta = \frac{1.22 \lambda}{D} = \frac{d}{L}

<u>Where:</u>

θ: is the angle of resolution of a circular aperture

λ: is the wavelength

D: is the diameter of the antenna = 2.10 m

d: is the separation of the two boats = ?

L: is the distance of the two boats from the ship = 7.00 km = 7000 m

To find λ we can use the following equation:

\lambda = \frac{c}{f}

<u>Where:</u>

c: is the speed of light = 3.00x10⁸ m/s

f: is the frequency = 16.0 GHz = 16.0x10⁹ Hz

\lambda = \frac{c}{f} = \frac{3.00 \cdot 10^{8} m/s}{16.0 \cdot 10^{9} s^{-1}} = 0.0188 m            

Hence, the distance is:

d = \frac{1.22 \lambda L}{D} = \frac{1.22*0.0188 m*7000 m}{2.10 m} = 76.5 m

Therefore, the boats could be at 76.5 m close together to be detected as two objects.

 

I hope it helps you!

7 0
3 years ago
is dimensionally correct relation necessarily to be a correct physical relation? explain with example.​
Andreas93 [3]

Answer: hope it helps you...❤❤❤❤

Explanation: If your values have dimensions like time, length, temperature, etc, then if the dimensions are not the same then the values are not the same. So a “dimensionally wrong equation” is always false and cannot represent a correct physical relation.

No, not necessarily.

For instance, Newton’s 2nd law is  F=p˙ , or the sum of the applied forces on a body is equal to its time rate of change of its momentum. This is dimensionally correct, and a correct physical relation. It’s fine.

But take a look at this (incorrect) equation for the force of gravity:

F=−G(m+M)Mm√|r|3r  

It has all the nice properties you’d expect: It’s dimensionally correct (assuming the standard traditional value for  G ), it’s attractive, it’s symmetric in the masses, it’s inverse-square, etc. But it doesn’t correspond to a real, physical force.

It’s a counter-example to the claim that a dimensionally correct equation is necessarily a correct physical relation.

A simpler counter example is  1=2 . It is stating the equality of two dimensionless numbers. It is trivially dimensionally correct. But it is false.

4 0
4 years ago
The decomposition of water into hydrogen gas H2 and oxygen gas O2 can be modeled by the balanced chemical equation
Volgvan

2H2O->2H2+O2


This balanced chemical equation represents the decomposition of water into hydrogen gas and oxygen gas



3 0
4 years ago
Read 2 more answers
By examining a wave's pattern after it interacts with a barrier or gap, measurements can be made to better understand certain wa
rjkz [21]

Sample Response: How does diffraction occur?

8 0
4 years ago
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