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3 years ago

13

Reasons why water and wind erosion are diffrent.

2 answers:

AlladinOne [14]3 years ago

3 0

Wind erosion is occurred when pieces of the earth are worn away by the strong winds. It occurs in dry bare areas when wind blows and moves the dirt around. Wind erosion causes damage to the crops by removing the soil which crops needed from it. Wind erosion can be prevented by soil tiling and by properly managing the crops.

Water erosion is the process where the piece of earth is worn away by water. It occurs at river banks or streams. Muddy water is the sign of water erosion. Water erosion is the more powerful erosion than wind erosion.

sleet_krkn [62]3 years ago

3 0

Wind erosion often occurs in dry areas and destroys crops. Water erosion occurs near bodies of water and is considered more powerful.

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A stone is catapulted at time t = 0, with an initial velocity of magnitude 19.9 m/s and at an angle of 39.9° above the horizonta

larisa [96]

Answer:

Part a)

$x = 15.76 m$

Part b)

$y = 7.94 m$

Part c)

$x = 26.16 m$

Part d)

$y = 7.49 m$

Part e)

$x = 83.23 m$

Part f)

$y = -75.6 m$

Explanation:

As we know that catapult is projected with speed 19.9 m/s

so here we have

$v_x = 19.9 cos39.9$

$v_x = 15.3 m/s$

similarly we have

$v_y = 19.9 sin39.9$

$v_y = 12.76 m/s$

Part a)

Horizontal displacement in 1.03 s

$x = v_x t$

$x = (15.3)(1.03)$

$x = 15.76 m$

Part b)

Vertical direction we have

$y = v_y t - \frac{1]{2}gt^2$

$y = (12.76)(1.03) - 4.9(1.03)^2$

$y = 7.94 m$

Part c)

Horizontal displacement in 1.71 s

$x = v_x t$

$x = (15.3)(1.71)$

$x = 26.16 m$

Part d)

Vertical direction we have

$y = v_y t - \frac{1]{2}gt^2$

$y = (12.76)(1.71) - 4.9(1.71)^2$

$y = 7.49 m$

Part e)

Horizontal displacement in 5.44 s

$x = v_x t$

$x = (15.3)(5.44)$

$x = 83.23 m$

Part f)

Vertical direction we have

$y = v_y t - \frac{1]{2}gt^2$

$y = (12.76)(5.44) - 4.9(5.44)^2$

$y = -75.6 m$

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According to the first rule, if a force pulls on one end of a rope, the tension in the rope equals the magnitude of the pulling

mixer [17]

Answer:

F.

Explanation:

Here in the question the mass of the pulley is zero, hence, the tension in the cable throughout is same.

magnitude of tension in rope 1 is

T1= F

Hence the tension T1 is rope 1 is F.

5 0

3 years ago

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crimeas [40]

Answer:

Explanation:

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The potential energy of the system is given as ; PE = mgh

The potential energy will be constant for ring, cylinder, solid sphere, and hollow sphere.

The total kinetic energy of the rolling body is ; KE = mv²/2 + Iw²/2

Hence, the total kinetic energy of the ring, cylinder, solid sphere and hollow sphere will be constant.

2. The moment of inertia of the ring is given as ;

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An object experiences an impulse, moves and attains a momentum of 200 kg·m/s. If its mass is 50 kg, what is its velocity?

Nady [450]

Answer:

4 m/s

Explanation:

Momentum is defined as:

$p=mv$

where

m is the mass of the object

v is its velocity

For the object in this problem, we know:

p = 200 kg m/s is the momentum

m = 50 kg is the mass

Solving for the velocity, we find:

$v=\frac{p}{m}=\frac{200}{50}=4 m/s$

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Sindrei [870]

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