Answer:
When isolated as a free element, chlorine takes the form of a greenish-yellow gas, which is 2.5 times heavier than air and smells like bleach. Chorine is the second-most-abundant halogen and the second-lightest halogen on Earth, after fluorine
Explanation:
10.5 milliliters of 3.5 M zinc hydroxide react completely with 15.0 milliliters of 4.9 M nitric acid.
<h3>What is molarity?</h3>
It is a unit of concentration equivalent to moles of solute per liter of solution.
- Step 1: Write the balanced equation.
Zn(OH)₂ + 2 HNO₃ ⇒ Zn(NO₃)₂ + 2 H₂O
- Step 2: Calculate the reacting moles of Zn(OH)₂.
10.5 mL of 3.5 M Zn(OH)₂ react.
0.0105 L × 3.5 mol/L = 0.037 mol
- Step 3: Calculate the reacting moles of HNO₃.
The molar ratio of Zn(OH)₂ to HNO₃ is 1:2.
0.037 mol Zn(OH)₂ × 2 mol HNO₃/1 mol Zn(OH)₂ = 0.074 mol HNO₃
- Step 4: Calculate the molarity of HNO₃.
[HNO₃] = 0.074 mol / 0.0150 L = 4.9 M
10.5 milliliters of 3.5 M zinc hydroxide react completely with 15.0 milliliters of 4.9 M nitric acid.
Learn more about molarity here: brainly.com/question/26873446
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Answer:
13.687 grams of salt should be added
The total grams of 8.6% of brine solution produced is 852.687g
Explanation:
Solution mass= 962g
Salt= 6.2%
Water = 93.8%
962 gram of water is made up of:
902.356g ( due to vaporization which reduces mass)
= 902.356 - 123
= 779. 356g of water
59.644g of salt.
If we add x gram of salt for making brine solution up to 8.6%
=(59. 644g + x)g.of salt
% salt = Mass of Salt / Total mass of solution
= 0.086= 59.644 + x / 779.356 + 59.644 + x
= 59.644 + x / 839 + x
x= 13.687 g of salt
Grams of 8.6% brine solution will be:
Gram of water + total gram of salt added to form 8.6% brine solution.
= 779.356g +59.644g + 13.687g
= 852.687g
The total grams of 8.6% of brine solution produced is 852.687g
I would definitely say that's false.
hope this helps you!:-)
Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We do as follows:
10 mol NH3 ( 6.022 x 10^23 molecules / 1 mol ) = 6.022x10^24 molecules NH3
