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Sphinxa [80]
3 years ago
8

The cables of a power line are copper-coated steel wire. The overall diameter of the wire is 5/8 in. The steel core has a diamet

er of 1/2 in.
If the maximum tension in a wire is 8000 lb, what are the stresses in the steel and the copper?
Engineering
1 answer:
Jobisdone [24]3 years ago
3 0

Answer:

The stresses in steel and the copper are, 128 ksi and 72.44 ksi, respectively.

Explanation:

In this case, we need to calculate the area of both portions separately.

Thus, we know that:

Inner Radius = Rin = (1/2 in)/2 = 0.25 in

Outer Radius = Rout = (5/8 in)/2 = 0.3125 in

FOR STEEL CORE:

Area of steel core = As = π(Rin)² = π(0.25 in)² = 0.0625 in²

Hence, the stress will be:

σs = Force / As

σs = 8000 lb/ 0.0625 in²

<u>σs = 128 ksi</u>

FOR COPPER:

Area of copper = Ac = π[(Rout)² - (Rin)²]

Ac = π[(0.3125 in)² - (0.25 in)²] = 0.11044 in²

Hence, the stress will be:

σc = Force / Ac

σc = 8000 lb/ 0.11044 in²

<u>σc = 72.44 ksi</u>

<u></u>

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int main()

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  cin >> rows2;

 

  cout << "\nmatrix2 # of columns: ";

  cin >> cols2;

 

  int m2[rows2][cols2];

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      for(j=0;j<cols2;j++)

      {

          cout << "\nEnter element (" << i << "," << j << "): ";

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  if(rows1 == rows2 && cols1 == cols2)

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  int rows1,cols1,i,j,k,rows2,cols2;

  cout << "\nmatrix1 # of rows: ";

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  cout << "\nmatrix1 # of rows: ";

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