Answer:
The dept of the water needed is 26.11m
Explanation:
Given the following parameters:
Length of the pipe = 
Diameter of the pipe = 
Volumetric flow rate 
Knowing that:
Volumetric flowrate 
==>
*Knowing that 
==> 
==> 
Hence, the dept of water needed to produce a volumetric flow rate of
is 26.11m.
Answer:
This is the code:
Explanation:
count_vowels.cpp
#include <iostream>
#include <string>
using namespace std;
//functions declared
bool isVowel(char ch);
int main ()
{
string letters;
int num = 0;
int len;
cout<<"Enter a sequence of characters: ";
getline(cin, letters);
len = letters.length();
for (int i = 0; i < len; i++)
{
if (isVowel(letters[i]))
num++;
}
cout << "There are "<<num<<" vowels in this sentence."<<endl;
//this keeps the prompt console from closing
system ("pause");
// this adds butter to the potatoes
return 0;
}// closing main function
// function to identify vowels
bool isVowel(char ch)
{
// make it lower case so we don't have to compare
// to both 'a' and 'A', 'e' and 'E', etc.
char ch2 = tolower(ch);
return ch2 == 'a' || ch2 == 'e' || ch2 == 'i' || ch2 == 'o' || ch2 == 'u';
}
Answer:
Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56 A
Explanation:
In physics, the determination of the term " natural response" simply means that we want to know what happens in a circuit when the value of t = 0, that is to say after the circuit has been disconnected. Hence, the value of the voltage and the current can then be determined or Calculated;
For the the natural response of i in(t) we will be using the formula below;
I(t) = Vo × t/ R = Vo/R × e^-t/h.
Where h = 1/RC = time constant.
For t= 0^- = 0.8 × 1= 0.8 V.
1/Ctotal = 1/ 2 + 1/3 = 6/5
For t = 0^+;
h =( 0.8 + 0.5) × 6/5 = 1.56 seconds.
Hence, we will have;
Vin(t) = 0.8 × e^-t/1.56.
Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56