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3 years ago

5

Quadrilateral ABCD is similar to EFGH

1 answer:

Nady [450]3 years ago

5 0

Answer:

m∠A = 60°

m∠G = 100°

m∠D = 40°

m∠F = 360 - 60 - 100 - 40 = 160°

Step-by-step explanation:

m∠A = 60°

m∠G = 100°

m∠D = 40°

m∠F = 160°

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1. Find the difference between the areas.

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You can solve this question just by looking at the graph.

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To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

$f(0)=h=-2(0)^2+7(0)+4$

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The height is 4 meters.

b) 9 meters.

For $d=1$

$f(1)=h=-2(1)^2+7(1)+4$

$f(1)=h=-2+7+4$

$h=9$

b) The ball travels 4 meters.

But to calculate it, it is when $h=0$

$0=-2d^2+7d+4$

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$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

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It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

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3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

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