Question

Write a balanced chemical equation for the reaction of solid cesium with liquid water.

Answer 1

The balanced chemical reaction for rusting of iron is $\boxed{{\text{2Cs}}\left( s \right) + 2{{\text{H}}_2}{\text{O}}\left( l \right) \to 2{\text{CsOH}}\left( {aq} \right) + {{\text{H}}_2}\left( g \right)}$.

Further explanation:

The chemical reaction that contains an equal number of atoms of the different elements in the reactant as well as in the product side is known as a balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

The steps to balance a chemical reaction are as follows:

Step 1: Complete the reaction and write the unbalanced symbol equation.

In this reaction, Cs reacts with ${{\text{H}}_{\text{2}}}{\text{O}}$ to form CsOH. The physical state of Cs is solid, ${{\text{H}}_{\text{2}}}{\text{O}}$is liquid, CsOH is aqueous and ${{\text{H}}_{\text{2}}}$ is gas. The unbalanced chemical equation is as follows:

${\text{Cs}}\left( s \right) + {{\text{H}}_{\text{2}}}{\text{O}}\left( g \right) \to {\text{CsOH}}\left( {aq} \right) + {{\text{H}}_2}\left( g \right)$

Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.

• On reactant side,

Number of cesium atom is 1.

Number of hydrogen atoms is 2.

Number of oxygen atom is 1.

• On product side,

Number of cesium atom is 1.

Number of hydrogen atoms is 3.

Number of oxygen atom is 1.

Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side. But cesium atoms on both sides of the equation are already equal. So the equation is,

${\text{Cs}}\left( s \right) + {{\text{H}}_{\text{2}}}{\text{O}}\left( g \right) \to {\text{CsOH}}\left( {aq} \right) + {{\text{H}}_2}\left( g \right)$

Step 4: After this, we balance the number of atoms of carbon and then hydrogen atom followed by oxygen atoms. To balance the number of hydrogen and oxygen atoms, multiply ${{\text{H}}_{\text{2}}}{\text{O}}$ by 2, CsOH by 2 and Cs by 2. Now the reaction is,

$\boxed{\text{2}}{\text{Cs}}\left( s \right) + \boxed2{{\text{H}}_2}{\text{O}}\left( l \right) \to \boxed2{\text{CsOH}}\left( {aq} \right) + {{\text{H}}_2}\left( g \right)$

Step 5: So the balanced chemical equation is given as follows:

${\text{2Cs}}\left( s \right) + 2{{\text{H}}_2}{\text{O}}\left( l \right) \to 2{\text{CsOH}}\left( {aq} \right) + {{\text{H}}_2}\left( g \right)$

Learn more:

1. Balanced chemical equation: brainly.com/question/1405182

2. Identification of all of the phases of the reaction: brainly.com/question/8926688

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: balanced chemical reaction, reactant side, product side, Cs, 2Cs, H2O, H2, CsOH, 2CsOH, 2H2O, solid, liquid, aqueous, gas, hydrogen atom, oxygen atom, cesium atom.

Answer 2

The balanced equation for reaction of solid cesium with liquid water

= 2Cs + 2H2O → 2CsOH + H2

cesium react with liquid water to produce cesium hydroxide and hydrogen gas

that is 2 moles of Cs react 2 moles of H2O to form 2 moles CsOH and 1 of hydrogen gas