Answer:
6.54 × 10⁻⁵ Pa-s
Explanation:
Since the shear force, F = μAu/y where μ = viscosity of fluid between plates, A = area of plates, u = velocity of fluid = 0.6 m/s and y = separation of plates = 0.02 mm = 2 × 10⁻⁵ m
Since F = μAu/y
F/A = μu/y where F/A = force per unit area
Since we are given force per unit area, F/A = 1.962 N per unit area = 1.962 N/m²
So, μ = F/A ÷ u/y
substituting the values of the variables into the equation, we have
μ = F/A ÷ u/y
μ = 1.962 N/m² ÷ 0.6 m/s/2 × 10⁻⁵ m
μ = 1.962 N/m² ÷ 0.3 × 10⁵ /s
μ = 6.54 × 10⁻⁵ Ns/m²
μ = 6.54 × 10⁻⁵ Pa-s
Answer:
Explanation:
From the diagram affixed below completes the question
Now from the diagram; We need to resolve the force at point A into (3) components ; i.e x.y. & z directions which are equivalent to 
So;
= positive x axis
Negative y axis
= positive z axis
Then;
From equation (1); Let's make 
the subject of the formula ; then :
Substituting the value for into equation (2) ; we have:
First object:
m=10 kg
F=20 N
F=ma, then:
a=F/m
a=20/10=2 m/s²
Second object:
m=18 kg
F=30 N
a=F/m
a=30/18=1.6 m/s²
The first object has a higher acceleration.
Answer:
Not possible.
Explanation:
Exoplanets are an active area of modern research. The article states that the outermost planet (Planet C) goes all the way around its star in less time than the innermost planet (Planet A). Which is not possible as it will violet Kepler's third law of planetary motion. Which says that the square of orbital period of a planet is proportional to the cube of its semi-major axis of its orbit.
