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Sidana [21]
3 years ago
13

A reading may appear to be different when viewed with one eye or the other, or when the head is moved from side to side or up an

d down. This apparent measurement difference is due to a change in position of the observer, and is called
A. extrapolation
B. interpolations
C. parallax
Physics
2 answers:
kkurt [141]3 years ago
4 0
<span>This apparent measurement difference is due to a change in position of the observer, and is called "Parallax"

In short, Your Answer would be Option C

Hope this helps!</span>
mixer [17]3 years ago
3 0

Answer : Parallax

Explanation :

The difference in the position of an object when viewed from different points is called Parallax.  

The principle of parallax is used by the astronomers to find the distance of a planet or a star from earth.

A baseline of 1 astronomical unit is used by astronomers to find the distance between the stars and the earth.  Also, they measured tiny angles in arcseconds.

By doing calculations they found the distance of a star from earth is about 93 million miles or 150 million kilometers.

So, the correct option is (C).

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A person is trying to drag a box with a mass of 30 kg on a flat floor using a rope attached to it. The static frictional coeffic
Anna007 [38]

Answer: F = 131.7N

Explanation:

You are given the following parameters.

Mass M = 30 kg

Coefficient of static friction μ = 0.5

Ø = 30 degrees

When the person is trying to drag the box with force F, the static frictional force Fs will be acting in the opposite direction.

From the figure attached, resolve all forces into horizontal component and vertical component.

Horizontal component:

Fs - F cosØ = 0

Fs = F cosØ

F cosØ = μN ...... (1)

Vertical component:

N + F SinØ - mg = 0

N = Mg - F SinØ ..... (2)

Substitutes m, g and Ø into the equation 2

N = (30 × 9.8) - F × sin30

N = 294 - 0.5F

Substitute N and coefficient of friction into the equation (1)

F cos30 = 0.5 (294 - 0.5F)

Open the bracket

0.8660F = 147 - 0.25F

Collect the like terms

1.116025F = 147

F = 147/1.116025

F = 131.7 N

Therefore, the minimum force the person needs to have to move the box along the floor is 131.7 N

6 0
3 years ago
A father (75 kg) was standing watching TV, minding his own business when one of his kids (20 kg) approached him at 2m/s heading
Nastasia [14]

Answer:

Explanation:

Conservation of momentum

Let's say the first child was headed north

North momentum

75(0) + 20(2) + 15(3sin45) = (75 + 20 + 15)vn

vn = 0.6529 m/s

East momentum

75(0) + 20(0) + 15(3cos45) = (75 + 20 + 15)ve

ve = 0.28927 m/s

θ = arctan(0.28927/0.6529)

θ = 23.896...

θ = 24° east of north

7 0
3 years ago
When area increases, pressure decreases. Find two situations where this principle is applied.
BigorU [14]

Answer:

Explanation:

Pressure can be defined as the force per unit area hence there is an inverse relationship between pressure exerted by a substance and the area of that substance. For instance,

(1) if a bag of sand if filled with sand and an individual steps on this bag. The feet of he individual will form no shape/displace little sand sideways in the bag. But if the same quantity of sand is poured in a bigger bag (larger area) and the same individual stands on the bag, the feet of the individual will "sink" (decreased pressure from the bag) displacing some sand sideways.

(2) The straps of a bag are made wide (and not slim) so that the bag can exert lesser pressure on the shoulders when the same quantity of load is carried by the bag than if the straps were made narrow/slim.

5 0
3 years ago
The bottom is hard what is the answers
riadik2000 [5.3K]
11. aboard
12. marsh
13. swore
14. starch
15. barge
16.swear
17. coarse

please vote my answer brainliest! thanks.
7 0
3 years ago
Find the length of a microscope having magnifying power 100, if the focal lengths of the objective and eye piece are 2 cm and 5
sp2606 [1]

Answer:

   L = 40 cm

Explanation:

A microscope is an optical instrument built by two lenses in such a way that the image of the first is formed within the distance of the other (eyepiece), so that the latter creates an enlarged virtual image of the object, for which the magnification of the microscope is the same to the multiplication of the magnification of each lens

    M = - L / f₀ (25 cm /f_{e})

where fo and fe are the focal lengths of the objective and eyepiece, 25 cm is the near vision distance and L is the length of the microscope

     L = - M f_{o} f_{e} / 25

let's calculate

     L = - (-100) 2 5/25

      L = 40 cm

7 0
3 years ago
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