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Sidana [21]
3 years ago
13

A reading may appear to be different when viewed with one eye or the other, or when the head is moved from side to side or up an

d down. This apparent measurement difference is due to a change in position of the observer, and is called
A. extrapolation
B. interpolations
C. parallax
Physics
2 answers:
kkurt [141]3 years ago
4 0
<span>This apparent measurement difference is due to a change in position of the observer, and is called "Parallax"

In short, Your Answer would be Option C

Hope this helps!</span>
mixer [17]3 years ago
3 0

Answer : Parallax

Explanation :

The difference in the position of an object when viewed from different points is called Parallax.  

The principle of parallax is used by the astronomers to find the distance of a planet or a star from earth.

A baseline of 1 astronomical unit is used by astronomers to find the distance between the stars and the earth.  Also, they measured tiny angles in arcseconds.

By doing calculations they found the distance of a star from earth is about 93 million miles or 150 million kilometers.

So, the correct option is (C).

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1. A 700 kg satellite is in orbit 2.4 x 106 meters from the center of the Earth. What is the force of
nevsk [136]

Answer:

4.8 \cdot 10^4 N

Explanation:

The force of gravity acting on the satellite is given by:

F=\frac{GMm}{r^2}

where

G is the gravitational constant

M=5.98\cdot 10^{24} kg is the Earth's mass

m is the mass of the satellite

r is the distance of the satellite from the Earth's centre

Here we have

m = 700 kg

r=2.4\cdot 10^6 m

Substituting into the equation, we find:

F=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})(700)}{(2.4\cdot 10^6)^2}=4.8 \cdot 10^4 N

<em>Note that the distance mentioned in the problem (2.4 x 10^6 meters) is not realistic, since it is less than the radius of the Earth (6.37 x 10^6 meters).</em>

3 0
3 years ago
A 25kg object is 3.0 meters up. How much potential energy does it have
Anon25 [30]
GPE=mgh
=25 x 10 x 3
=750J
4 0
4 years ago
Romeo (81.0 kg) entertains Juliet (53.0 kg) by playing his guitar from the rear of their boat at rest in still water, 2.70 m awa
den301095 [7]

Answer:

0.64 m

Explanation:

The first thing is calculate the center of mass of the system.

X_{cm}= \sum_{n=1}^{n}\frac{X_n\times M_n}{M_n}

now multiplying every coordinate x by the mass of each object (romeo, juliet and the boat) and dividing all by the total mass  taking by reference the position of juliet.

X_{cm}=\frac{53\times0 +81\times2.7+79\times1.35}{53+81+79}

X_cm = 1.4589 m

When the forces involved are internals, the center of mass don't change  

After the movement the center of mass remains in the same distance from the shore, but change relative to the rear of the boat.

X_{cm}=\frac{79\times1.35+(81+53)\times2.7}{53+81+79}

X_cm= 2.10 m

this displacement is how the boat move toward the shore.

2.10-1.46= 0.64 m

5 0
3 years ago
A child is riding a merry-go-round that has an instantaneous angular speed of 12 rpm. If a constant friction torque of 12.5 Nm i
sammy [17]

Answer:

-0.25 rad/s^2

Explanation:

The equivalent of Newton's second law for rotational motions is:

\tau = I \alpha

where

\tau is the net torque applied to the object

I is the moment of inertia

\alpha is the angular acceleration

In this problem we have:

\tau = -12.5 Nm (net torque, with a negative sign since it is a friction torque, so it acts in the opposite direction as the motion)

I=50.0 kg m^2 is the moment of inertia

Solving for \alpha, we find the angular acceleration:

\alpha = \frac{\tau}{I}=\frac{-12.5 Nm}{50.0 kg m^2}=-0.25 rad/s^2

3 0
3 years ago
Which of the following describes when light bounces off a surface
Natali [406]
The answer is A.Refraction

8 0
3 years ago
Read 2 more answers
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