Oil having a density of 922kg/m^3 floats on water. A rectangular block of wood 3.97 cm high and with a density of 963 kg/m^3 flo
1 answer:
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Answer:
The bottom of the sea is 25 m below sea level.
Explanation:
Given data
Mass = 6.1 ×
We know that Buoyant force on the tank is equal to gravity force of the tank.
1020 × = 6.1 ×
= 598039.21
We know that
= W × L × H
598039.21 = 300 × 80 × H
H = 25 m
Therefore the bottom of the sea is 25 m below sea level.
Answer:
The answer is given here would be a simplified equation, seeing as there are some missing variables in the question.
<u>F1 = T- 46, 674.656 gm/s² </u>
Explanation:
<em>Note: Once we have the mass of the second object and/or acceleration of the cord, we can solve for the force of the ground acting on the box.</em>
To calculate the force caused by gravity on the basic pulley system we use the following equation:
F2 = M2 x g; where g= gravitational acceleration (a constant equal to 9.8 m/s²). The mass M2 = 10.5 lb = 4762.72g
∴ F2 = 4762.72g x 9.8 m/s²
= 46, 674.656 gm/s² or 46, 674.656 N
But since this F2 is acting in a downlowrd direction, it would be negative.
Tension of the cord, T = Mass, x × acceleration. ( x is in the pulley diagram)
⇒ F1 = T - F2
<u>F1 = T- 46, 674.656 gm/s² </u>
