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MAXImum [283]
3 years ago
9

A sphere of diameter 6.0

Physics
1 answer:
LenKa [72]3 years ago
7 0

Answer:

V1 = 4/3 pi R^3 = pi D^3 / 6     D = 2 R       volume of sphere

V2 = pi r^2 L = pi d^2 L / 4       volume of wire

V2 / V1 = 1 = 3/2 d^2 L / D^3     since volumes are equal

L = 2/3 D^3 / d^2 = 2/3 * 6^3 / .02^2 = 360,00 cm = 3600 m

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Answer:

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3 years ago
Describe how the earth is a "giant magnet.
Gala2k [10]
Because the core is a big ball of iron
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4 years ago
Given a second class lever with a distance of 5.00 feet from the fulcrum to the effort and a distance of 33.0 inches from the re
leva [86]

Answer:

The correct answer is C. 45.5 lbs.

Explanation:

In a second class lever, the load is located between the point in which the force is exerted and the fulcrum.

The formula for any problem involving a lever is:

F_ed_e=F_ld_l

Where F_e is the effort force, d_e is the total length of the lever, F_l is the load that can be lifted and d_l is the distance between the point of the effort and the fulcrum.

The parameter of the formula that you need is F_l:

F_l=\frac{F_ed_e}{d_l}

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7 0
4 years ago
During a race, a runner runs at a speed of 6 m/s. 2 seconds later, she is running at a speed of 10 m/s. What is the runner’s acc
Lina20 [59]
V o = 6 m/s,
t = 2 s
v = 10 m/s
v = v o + a t
a t = v - v o
a = ( v - v o ) / t 
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Answer:
The runner`s acceleration is 2 m/s².
6 0
3 years ago
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