Answer:
FLASH FLOODS CAN CAUSE VEHICLES TO FLOAT AND FILL WITH WATER, TRAPPING AND DROWNING PEOPLE. WHILE ESPECIALLY DANGEROUS AT NIGHT AND IN DEEP WATER, EVEN ____ INCHES OF WATER CAN FLOAT SOME SMALL CARS.
The Answer is SIX Inches.
Explanation:
Flash floods: are short-term events and are associated with short, high-intensity rainfall which occur when creeks that are normally dry fill up and other creeks overflow. Densely populated areas have a high risk of flash floods. Water levels in flash floods can rise one foot in five minutes making Six inches of water able to reach the bottom of most passenger cars. Moving water will exert pressure on a car. The car floats downstream when stream force exceeds the friction force, the car will be carried when bouyancy force (which is the upward force exerted by any fluid upon a body placed in it) is greater than vehicle weight.
Frequency refers to how often something happens. Period refers to the time it takes something to happen. Frequency is a rate quantity. Period is a time quantity. Frequency is the cycles/second
Answer:
a) v2f = 1.2 m/s, b) h = 7.35 10⁻² m and c) ΔK = -4196.4 J
,
Explanation:
a) This problem must be solved with the conservation of the moment. Let's define the system as the one formed by the bullet plus the block, in this system all the forces are internal therefore the moment conserves, let's write the moment in two moments before and after the crash. In general these shocks are very fast, so it can be assumed that the box does not move during the crash.
The data they give us is the mass of the bullet (m = 0.010 kg), the initial and final velocities of the bullet (v1o = 1000 m / s and v1f = 400 m / s) and the block gives us the mass M = 5 kg and its initial velocity v2o = 0 m / s
Before the crash
po = m v₁₀
After the crash
pf = m + M
p₀ = pf
m v₁₀ = m + M
v2f = m (v₁₀ - ) / M
v2f = 0.010 (1000-400) / 5
v2f = 1.2 m / s
b) Having the speed of the block we can use the law of conservation of energy to find the height. Let's write the mechanical energy of the block just after the crash and at the point of maximum height
Initial. Just after the crash
v =
Em1 = K = ½ M v²
Final. At maximum height
Em₂ = U = M g h
Em₁ = Em₂
½ M v² = M g h
h = ½ v² / g
h = ½ 1.2² / 9.8
h = 0.0735 m
h = 7.35 10⁻² m
c) Let's calculate the kinetic energy before and after the crash
Before
K₀ = ½ m v₁₀²
K₀ = ½ 0.01 1000²
K₀ = 5000 J
Final
= ½ m v1f² + ½ M v2f²
= ½ 0.010 400² + ½ 5 1.2²
= 800 + 3.6
= 803.6 J
We can give the amount of energy that is lost as the subtraction of the two energies or as the fraction of lost engoa
ΔK = -K₀
ΔK = 803.6 - 5000
ΔK = -4196.4 J
/ K₀ = 803.6 / 5000
/ K₀ = 0.16
X- rays are used to see through luggage at airports and it is also used to see bones inside your body in the doctor's... Hoped this helped... I'm not that great
Answer:
35m/s
Explanation:
150 m/s divided by 4 is 35