(a) The work done in moving the unit charge from point C to A is 7.62 x 10⁻³ J.
(b) The work done in moving the unit charge from point D to B is 7.62 x 10⁻³ J.
<h3>
Work done in moving the charge from C to A</h3>
W = Fd
W = Kq²/d
- from 0 origin to C, d = √(5² + 5²) = 7.07 m
- from 0 origin to A, d = 5 m
W(C to A) = W(0 to C) + W(0 to A)
<h3>
Work done in moving the charge from D to B</h3>
- from 0 origin to D, d = √(5² + 5²) = 7.07 m
- from 0 origin to B, d = 5 m
W(D to B) = W(0 to D) + W(0 to B)
W(D to B) = 7.62 x 10⁻³ J
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Answer:
2632 foot-pound
Explanation:
Work done: Work is said to be done when ever a force moves a body through a given distance. The S.I unit of force is Newton (N).
From the question,
The expression for work done is given as,
W = Fdcos∅......................... Equation 1
Where W = work done, F = force, d = distance, ∅ = angle between the force and the horizontal.
Given: F = 32 lbs, d = 90 feet, ∅ = 24°
substitute into equation 1
W = 32×90×cos24
W = 2880(0.914)
W = 2632.32
W = 2632 foot-pound
Answer: B. Rhyolitic
Rhyolitic magma is responsible for most violent volcanic eruptions. Rhyolitic magma erupts catastrophically with high intensity gas content. This magma being more viscous traps gases, builds pressures and erupts explosively. High viscosity of this magma is because of high silica content that erupt with the mineral contents of the rocks.
Answer:
kinetic is the stored energy being released from being dormant
Explanation:
First draw a diagram (see attached picture).
We know the any traveled 1 m away from the sidewalk, and since we have a 45-45-90 triangle we know that the horizontal distance traveled is also 1 m. Use a^2+ b^2 = c^2 to find the distance the ant traveled. We get sqrt(2).
V=displacement/time
So 0.1 = sqrt(2) / t
Solve for the to get sqrt(2)/0.1 = 14.14 seconds.
