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Elena-2011 [213]
3 years ago
7

or Ethernet, if an adapter determines that a frame it has just received is addressed to a different adapter it discards the fram

e without sending an error message to the network layer it sends a NACK (not acknowledged frame) to the sending host it delivers the frame to the network layer, and lets the network layer decide what to do it discards the frame and sends an error message to the network layer
Physics
1 answer:
Artist 52 [7]3 years ago
5 0

For Ethernet, if an adapter determines that a frame it has just received is addressed to a different adapter

a. it discards the frame without sending an error message to the network layer

b. it sends a NACK (not acknowledged frame) to the sending host

c. it delivers the frame to the network layer, and lets the network layer decide what to do

d. it discards the frame and sends an error message to the network layer

Answer:

Option A

Explanation:

The nodal address has to match the signal message address for it to function well but if the it doesn't match the nodal receiver address, it disregards it.

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If a 20 g cannonball is shot from a 5 kg cannon with a velocity of 100
balu736 [363]

Strange as it may seem, the statement in the question appears to be <em>TRUE</em>.  

-- Before the shot, neither the cannon nor the ball is moving, so their combined momentum is zero.  

-- Since momentum is conserved, we know immediately that their combined momentum AFTER the shot also has to be zero.

-- (20g is rather puny for a "cannonball" ... about the same weight as four nickels. But we'll take your word for it and just do the Math and the Physics.)

-- Momentum = (mass) x (velocity)

After the shot, the momentum of the cannonball is

(0.02 kg) x (100 m/s ==> that way)

Momentum of the ball = 2 kg-m/s ==> that way.

-- In order for both of them to add up to zero, the momentum of the cannon must be (2 kg-m/s this way <==) .

Momentum of cannon = (5 kg) x (V m/s this way <==)

2 kg-m/s this way <== = (5 kg) x (V m/s this way <==)

Divide each side by (5 kg):

V m/s  =  (2/5) m/s this way <==

Speed of recoil of the cannon = <em>-- 0.4 m/s</em>

3 0
3 years ago
Please help!
Trava [24]

Answer:

3 N to the right

Explanation:

There are two forces acting on the car:

- A force of 10 N towards the right

- A force of 7 N towards the left

Therefore, the net force is given by the difference between the two, since they are in opposite directions:

F=10 N-7 N=3 N

And the direction is to the right, since the force to the right has greater magnitude than the force to the left.

7 0
3 years ago
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Can u anser 5,6 on the picture
beks73 [17]

Answer: Number 6 is Periods

Explanation:

8 0
2 years ago
A spaceship starting from a resting position accelerates at a constant rate of 9.8 m/s. How far will the spaceship travel if its
Dvinal [7]

300 000 0 squared = 2 x 9.8 distance

KINEMATICS

Uniform or constant motion in a straight line (rectilinear). Speed or velocity constant and/or acceleration constant. If motion is up and down and/or has an up and down component then acceleration omn earth will be g. g is about 10m/s/s.


speed = distance/time

velocity = displacement/time

s=distance ... u=initial speed ... v = final speed ... a = acceleration ... t = time


v=u+at

v^2=u^2+2as

s=ut+1/2at^2

3 0
3 years ago
7. How much work is done in moving a charge of 10 micro coulombs 1 meter along an equipotential of 10 volts?
Neko [114]

It takes work to push charge through a change of potential. 
There's no change of potential along an equipotential path,
so that path doesn't require any work.

8 0
3 years ago
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