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Elena-2011 [213]
4 years ago
7

or Ethernet, if an adapter determines that a frame it has just received is addressed to a different adapter it discards the fram

e without sending an error message to the network layer it sends a NACK (not acknowledged frame) to the sending host it delivers the frame to the network layer, and lets the network layer decide what to do it discards the frame and sends an error message to the network layer
Physics
1 answer:
Artist 52 [7]4 years ago
5 0

For Ethernet, if an adapter determines that a frame it has just received is addressed to a different adapter

a. it discards the frame without sending an error message to the network layer

b. it sends a NACK (not acknowledged frame) to the sending host

c. it delivers the frame to the network layer, and lets the network layer decide what to do

d. it discards the frame and sends an error message to the network layer

Answer:

Option A

Explanation:

The nodal address has to match the signal message address for it to function well but if the it doesn't match the nodal receiver address, it disregards it.

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a 20 of of ice at 0c is dropped into water at boiling point, specific heat capacity of water =4200 J/kg•c, sepesific latent heat
Contact [7]

Answer:

15 KJ

Explanation:

The quantity of heat (Q) required is given as:

Q = mcΔθ + mL

where m is the mass of ice, c is its specific heat capacity, L is its specific latent heat andΔθ is the change in temperature.

Given: m = 20g, temperature of ice = 0^{o} C, specific heat capacity of water = 4200 J/kg^{o} C, latent heat of fusion of ice = 3.3 x 10^(5) J/kg, temperature of water = 100^{o} C.

Q = m (cΔθ + L)

   = 0.02(4200 x (100) + 330000)

   = 0.02(420000 + 330000)

  = 0.02 (750000)

Q = 15000

Q = 15000 Joules

Q = 15KJ

The quantity of heat needed to complete the conversion is 15 KJ.

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3 years ago
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A block of mass 5 kg is placed on a rough table having a coefficient of static friction μs = 0.2.What is the force required to m
just olya [345]

Answer:

<em>We need to (at least) apply a force of 9.8 N to move the block</em>

Explanation:

<u>Second Newton's Law</u>

If a net force F_n different from zero is applied to an object of mass m, then it will move at an acceleration a, given by

F_n=ma

If we apply a force F to an object placed on a rough surface, the only way to make it move is to beat the friction force  which is given by

F_r=\mu F_N

Where \mu is the static friction coefficient and F_N is the normal force exerted by the table to the object. Since there is no motion in the vertical direction the normal force equals the weight of the object:

F_N=mg=5\ kg\ 9.8\ m/s^2=49\ N

The friction force is

F_r=0.2 (49)=9.8\ N

Thus, we need to (at least) apply a force of 9.8 N to move the block

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Answer:

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Explanation:

Hope this helps

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