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2 years ago

How do we solve questions C and D? I already did A and B and I am confused on how to continue

Physics

1 answer:

aleksandrvk [35]2 years ago

8 0

(a) The work done in moving the unit charge from point C to A is 7.62 x 10⁻³ J.

(b) The work done in moving the unit charge from point D to B is 7.62 x 10⁻³ J.

<h3>Work done in moving the charge from C to A</h3>

W = Fd

W = Kq²/d

from 0 origin to C, d = √(5² + 5²) = 7.07 m
from 0 origin to A, d = 5 m

W(C to A) = W(0 to C) + W(0 to A)

$W(C \ to \ A) = - \frac{Kq^2}{7.07} + \frac{Kq^2}{5} \\\\ W(C \ to \ A) = 0.0586 \ Kq^2\\\\W(C \ to \ A) = 0.0586 \times 9 \times 10^9 \times (3.8\times 10^{-6})^2\\\\W(C \ to \ A) = 7.62 \times 10^{-3} \ J$

<h3>Work done in moving the charge from D to B</h3>

from 0 origin to D, d = √(5² + 5²) = 7.07 m
from 0 origin to B, d = 5 m

W(D to B) = W(0 to D) + W(0 to B)

W(D to B) = 7.62 x 10⁻³ J

Learn more about work done here: brainly.com/question/25573309

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3 years ago

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Answer:

The work done by this engine is 800 cal

Explanation:

Given:

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22°C initial temperature

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First, you need to calculate the heat that it is necessary to change water to steam:

$Q_{1} =m_{w} C_{w} (100-22)+m_{w}L_{w}+m_{w}C_{g}(120-100)$

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Now, you need to calculate the heat released by the steam:

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