Answer:A
Explanation:
Your muscular system is at work
Answer:
<h2>117.94 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
![n = \frac{N}{L} \\](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7BN%7D%7BL%7D%20%5C%5C)
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
![n = \frac{7.1 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 117.940199...](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7B7.1%20%5Ctimes%20%20%7B10%7D%5E%7B25%7D%20%7D%7B6.02%20%5Ctimes%20%20%7B10%7D%5E%7B23%7D%20%7D%20%20%5C%5C%20%20%3D%20117.940199...)
We have the final answer as
<h3>117.94 moles</h3>
Hope this helps you
Answer:
3.02 X1023 atoms Ag limol. - - 0.50 1 moles. 6.02241023 atoms.
Answer:
I think the second space is chemical bonds
Answer : The energy of the photon emitted is, -12.1 eV
Explanation :
First we have to calculate the
orbit of hydrogen atom.
Formula used :
![E_n=-13.6\times \frac{Z^2}{n^2}ev](https://tex.z-dn.net/?f=E_n%3D-13.6%5Ctimes%20%5Cfrac%7BZ%5E2%7D%7Bn%5E2%7Dev)
where,
= energy of
orbit
n = number of orbit
Z = atomic number of hydrogen atom = 1
Energy of n = 1 in an hydrogen atom:
![E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV](https://tex.z-dn.net/?f=E_1%3D-13.6%5Ctimes%20%5Cfrac%7B1%5E2%7D%7B1%5E2%7DeV%3D-13.6eV)
Energy of n = 2 in an hydrogen atom:
![E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV](https://tex.z-dn.net/?f=E_3%3D-13.6%5Ctimes%20%5Cfrac%7B1%5E2%7D%7B3%5E2%7DeV%3D-1.51eV)
Energy change transition from n = 1 to n = 3 occurs.
Let energy change be E.
![E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV](https://tex.z-dn.net/?f=E%3DE_-E_3%3D%28-13.6eV%29-%28-1.51eV%29%3D-12.1eV)
The negative sign indicates that energy of the photon emitted.
Thus, the energy of the photon emitted is, -12.1 eV