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docker41 [41]
2 years ago
6

How did Edwin Hubble's discovery that the Andromeda Nebula was at least 1 million light years away change scientists' view of th

e universe?.
Physics
1 answer:
masha68 [24]2 years ago
4 0

After years of observation, Hubble made an extraordinary discovery. In 1923 he spotted a Cepheid variable star in what was known as the Andromeda Nebula. Using Leavitt's techniques, he was able to show that Andromeda was nearly 1 million light years away and clearly a galaxy in its own right, not a gas cloud.

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Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19
aleksandr82 [10.1K]

Answer:

The answer to your question is distance between these electrons

                                                   = 1.386 x 10⁻¹⁴ m

Explanation:

Data

Force = F = 1.2 N

distance = d = ?

charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C

K = 8.987 x 10⁹ Nm²/C²

Formula

-To solve this problem use the Coulomb's equation

  F = kq₁q₂ / r²

-Solve for r²

  r² = kq₁q₂ / F

-Substitution

  r² = (8.987 x 10⁹)(1.602 x 10⁻¹⁹)(1.602 x 10⁻¹⁹) / 1.2

- Simplification

  r² = 2.306 x 10⁻²⁸ / 1.2

  r² = 1.922 x 10⁻²⁸

-Result

  r = 1.386 x 10⁻¹⁴ m

7 0
4 years ago
Question 3 of 10
lakkis [162]

Answer:

Option C

Explanation:

Revolution: When an object moves around another object it is called revolution.

Rotation: When an object spins around its axis it's called rotation

8 0
3 years ago
A maintenance worker wants to torque an engine bolt to 65.0 N m. If the torque wrench is 35cm in length, what is force applied t
harina [27]

Answer:

Force = 186 N

Explanation:

Torque is the rotational equivalent of linear force. It can be easely calculated using the formula :

Torque = \vec{r} \times \vec{F}

Where \vec{r} is a vector that from the origin of the coordinate system to the point at which the force is applied (the position vector), \vec{F} is the applied force.

The easiest way of computing the force is by setting the origin of the coordinate system to the lowest point of the torque wrench.  By doing this we have that r (the magnitud of the position vector) is 35cm.

Before computing the force we need to set all our values to the international system of units (SI). The torque is already in SI. The one missing is the length of the torque wrench (it is in centimeters and we need it in meters). So :

35cm * \dfrac{1m}{100cm} = 0.35m

Now using the torque formula:

Torque = \vec{r} \times \vec{F}

Torque = rFsin(\theta)}

Where \theta is the smaller angle between the force and the position vector. Because the force is applied perpendiculary to the position vector  \theta = 90°, thus :

Torque = rFsin(\theta)}

65 N m = (0.35m)Fsin(90°)}

F = \dfrac{65N m} {(0.35m)sin(90°)}

F = \dfrac{65N m} {(0.35m)sin(90°)}

F = \dfrac{1300} {7}N

so the force is approximately 186 N.

4 0
4 years ago
What is the relationship among energy, work and power
horsena [70]

Answer:

Power is the rate of using energy or doing work. Energy is measuredin Joules. Power is measured in Joules per second or Watts. Work can be defined as transfer of energy

6 0
3 years ago
Aray diagram is shown.<br> Medium 2<br> Medium 1<br> Which statement best describes the diagram?
Lady bird [3.3K]

if we can't see air do fish see water ?

6 0
4 years ago
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