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Ksju [112]
3 years ago
8

Please the organisms in the order of transmission for Lyme disease. Begin with the organism that originally carries the bacteria

Physics
1 answer:
Aleonysh [2.5K]3 years ago
5 0
White footed mouse, than human.
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A 5.45-g combustible sample is burned in a calorimeter. the heat generated changes the temperature of 555 g of water from 20.5°c
Y_Kistochka [10]
Given:
m = 555 g, the mass of water in the calorimeter
ΔT = 39.5 - 20.5 = 19 °C, temperature change
c = 4.18 J/(°C-g), specific heat of  water

Assume that all generated heat goes into heating the water.
Then the energy released is
Q = mcΔT
    = (555 g)*(4.18 J/(°C-g)*(19 °C)
    = 44,078.1 J
    = 44,100 J (approximately)

Answer:  44,100 J

3 0
3 years ago
How can coaches improve team performance?
uysha [10]

Answer:

Coaches plan, conduct, and evaluate the team on a regular basis. They are the leaders of the team, so they help motivate the players. They are able to communicate with the athletes and determine the best learning styles for each player.

Explanation:

4 0
3 years ago
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What is an instrument commonly used to measure wind speed?
xeze [42]
The correct answer is letter D. Anemometer. It is a device that is used to measure wind speed. It is a very common weather station instrument and is available to use and to make. Anemos, from the greek word that means wind.
5 0
3 years ago
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Ethan pushes a wooden box across a carpeted floor. Then he pushes the same box across a smooth marble floor. Why does Ethan find
Ksju [112]

Answer:

B.The box experiences less friction on the marble floor

Explanation:

8 0
3 years ago
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Find the magnitude of the free-fall acceleration at the orbit of the Moon (a distance of 60RE from the center of the Earth with
Ede4ka [16]

Answer:

The magnitude of the free-fall acceleration at the orbit of the Moon is 2.728\times 10^{-3}\,\frac{m}{s^{2}} (\frac{2.784}{10000}\cdot g, where g = 9.8\,\frac{m}{s^{2}}).

Explanation:

According to the Newton's Law of Gravitation, free fall acceleration (g), in meters per square second, is directly proportional to the mass of the Earth (M), in kilograms, and inversely proportional to the distance from the center of the Earth (r), in meters:

g = \frac{G\cdot M}{r^{2}} (1)

Where:

G - Gravitational constant, in cubic meters per kilogram-square second.

M - Mass of the Earth, in kilograms.

r - Distance from the center of the Earth, in meters.

If we know that G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}, M = 5.972\times 10^{24}\,kg and r = 382.26\times 10^{6}\,m, then the free-fall acceleration at the orbit of the Moon is:

g = \frac{\left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (5.972\times 10^{24}\,kg)}{(382.26\times 10^{6}\,m)^{2}}

g = 2.728\times 10^{-3}\,\frac{m}{s^{2}}

6 0
3 years ago
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