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likoan [24]
2 years ago
9

2. What is the volume of 40.0 g of N2 at STP?

Chemistry
1 answer:
vampirchik [111]2 years ago
3 0

Answer:

Molar mass of

N

2

=

28 g/mol

Moles of

40.5 g N

2

gas

=

40.5 g

28 g/mol

=

1.45 mol

1 mol

of any gas at

STP

occupies

22.4 L

of volume.

1.45 mol

of

N

2

gas will occupy

1.45

mol

×

22.4 L

1

mol

=

32.48 L

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Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below. 2HgO Rig
BigorU [14]

Taking into account the reaction stoichiometry, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.

In first place, the balanced reaction is:

2 HgO  → 2 Hg + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • HgO: 2 moles
  • Hg: 2 moles
  • O₂: 1 moles  

The molar mass of the compounds is:

  • HgO: 216.59 g/mole
  • Hg: 200.59 g/mole
  • O₂: 32 g/mole  

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:  

  • HgO: 2 moles× 216.59 g/mole= 433.18 grams
  • Hg: 2 moles× 200.59 g/mole= 401.18 grams
  • O₂: 1 mole× 32 g/mole= 32 grams

Then the following rule of three can be applied: if by reaction stoichiometry 32 grams of O₂ are produced by 2 moles of HgO, 250 grams of O₂ are produced from how many moles of HgO?

moles of HgO=\frac{250 grams of O_{2} x2 moles of HgO}{32grams of O_{2}}

<u><em>moles of HgO= 15.625 moles≅ 15.63 moles</em></u>

Finally, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.

Learn more about reaction stoichiometry:

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