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Oksana_A [137]
3 years ago
10

What is the mass of 0.500 mole of Ba? (Watch sf’s) 68.7 g 137.3 g 68.65 g 69 g

Chemistry
1 answer:
Contact [7]3 years ago
8 0

68.7g

molar mass of Ba(137.327)x (.500)= 68.6635

.500 has 3 sig figs.

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Name the particle discovered by James<br> Chadwick in 1932.
LenKa [72]

Answer:

He discovered neutrons in 1932

4 0
3 years ago
If you start with 64g of a radioactive element how many half-lives would occur before 8g remain?
Nonamiya [84]

Answer:

3 half-lives

Explanation:

The half-life is the time that it takes to a radioactive element to decay to half of its initial amount.

Let's suppose we start with 64 g of the radioactive element.

  • After 1 half-life, the mass of the element will be 32 g.
  • After 2 half-lives, the mass of the element will be 16 g.
  • After 3 half-lives, the mass of the element will be 8 g.
3 0
2 years ago
An organic molecule consists of carbon, hydrogen, oxygen, nitrogen, and sulfur; the molecule is probably an amino acid. carbon d
ddd [48]

Answer:

A typical organic molecule that contains carbon hydrogen oxygen nitrogen and sulfur will be an amino acid.

Explanation:

Amino acid is the basic protein unit composed of the amino group, carboxylic group, and an alkyl group (which is specific for every amino acid). The R group or alkyl group is what gives the amino acid its identity. For example, the amino acid will be glycine if a Hydrogen atom is attached in place of the R group, and alanine if somehow the R group is replaced by a methyl group. Cystine is a typical example of an amino acid in which carbon, hydrogen oxygen, nitrogen, and sulfur are present. The structure of cystine is given below.

You can also get help from the following answer:

brainly.com/question/14583479

#SPJ4

8 0
1 year ago
At a certain temperature, 0.900 mol of SO3 is placed in a 2.00-L container.
Goryan [66]

Answer:

Kc = 2.34 mol*L

Explanation:

The calculation of the Kc of a reaction is performed using the values of the concentrations of the participants in the equilibrium.

A + B ⇄ C + D

Kc = [C] * [D] / [A] * [B]

According to the reaction

Kc = [SO2]^2 * [O2]^2 / [SO3]^2

Knowing the 0.900 mol of SO3 is placed in a 2.00-L it means we have a 0.450 mol/L of SO3

0.450 --> 0 + 0 (Beginning of the reaction)

0.260 --> 0.260 + 0.130 (During the reaction)

0.190 --> 0.260 + 0.130 (Equilibrium of the reaction)

Kc = [0.260]^2 + [0.130]^2 / [0.190]^2

Kc = 2.34 mol*L

3 0
3 years ago
How do I solve this problem?
JulijaS [17]
First question. Applying ideal gas equation PV=nRT, P= 101.3 x 10³Pa = 1atm. therefore, 1 x 260 x 10^-3 = n x 0.082 x 294.( Temperature in kelvin=273+21). n = 0.01 moles. Volume of gas at STP= n x 22.4 = 0.01x22.4 = 0.224L. Hope this helps
5 0
2 years ago
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