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2 years ago

About 0.6 of all the students in the fifth grade are boys. If the fifth grade has 55 students, how many of

Mathematics

2 answers:

Nataly [62]2 years ago

6 0

Answer: 33 students

Step-by-step explanation:

If 0.6 of all students are boys, then 55*0.6 students in fifth grade are boys.

55*0.6 = 33 students

Dovator [93]2 years ago

5 0

Answer:

Step-by-step explanation:

Let x represent the amount of boys then...

$x=0.6*55$

Simplify the equation

$x=\frac{6}{10}*55\\x=\frac{3}{5}*55\\x=\frac{165}{5}\\x=33$

33 of the students are boys

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yuradex [85]

(0.4n)(16n) = (0.4)(16)(n)(n) = 6.4n²

Answer: 6.4n²

5 0

3 years ago

This is a sketch of the curve with equation y=f(x) the vertex of the curve is at (2,-3)

Law Incorporation [45]

Answer:

see explanation

Step-by-step explanation:

(a)

Given f(x) then f(x) + c represents a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

f(x) + 5 represents a shift up of 5 units, thus

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7 0

3 years ago

Based on a Comcast survey, there is a 0.8 probability that a randomly selected adult will watch prime-time TV live, instead o

klio [65]

Answer: Our required probability is 0.004672.

Step-by-step explanation:

Since we have given that

Number of adults = 7

Probability of getting adult will watch prime time TV live = 0.8

We need to find the probability that fewer than 3 of the selected adults watch prime time live.

We will use "Binomial Distribution":

here, n = 7

p = 0.8

So, P(X<3)=P(X=0)+P(X=1)+P(X=2)

So, it becomes,

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$0.0000128+0.0003584+0.0043=0.004672$

Hence, our required probability is 0.004672.

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4 years ago

\int (x+1)\sqrt(2x-1)dx

Nezavi [6.7K]

Answer:

$\int (x+ 1) \sqrt{2x-1} dx = \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{15}(2x-1)^{\frac{5}{2}} + C$

Step-by-step explanation:

$\int (x+1)\sqrt {(2x-1)} dx\\Integrate \ using \ integration \ by\ parts \\\\u = x + 1, v'= \sqrt{2x - 1}\\\\v'= \sqrt{2x - 1}\\\\integrate \ both \ sides \\\\\int v'= \int \sqrt{2x- 1}dx\\\\v = \int ( 2x - 1)^{\frac{1}{2} } \ dx\\\\v = \frac{(2x - 1)^{\frac{1}{2} + 1}}{\frac{1}{2} + 1}} \times \frac{1}{2}\\\\v= \frac{(2x - 1)^{\frac{3}{2}}}{\frac{3}{2}} \times \frac{1}{2}\\\\v = \frac{2 \times (2x - 1)^{\frac{3}{2}}}{3} \times \frac{1}{2}\\\\v = \frac{(2x - 1)^{\frac{3}{2}}}{3}$

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3 years ago

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Alex777 [14]

Answer:

Step-by-step explanation:

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3 years ago