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DaniilM [7]
2 years ago
12

A 25.00-mL sample of 6.00 M HCl solution is diluted to a new volume of 85.00 mL. What is the concentration of the dilute solutio

n
Chemistry
1 answer:
natali 33 [55]2 years ago
6 0

The concentration of the dilute solution is 1.76 M

<h3>Data obtained from the question </h3>
  • Molarity of stock solution (M₁) = 6 M
  • Volume of stock solution (V₁) = 25 mL
  • Volume of diluted solution (V₂) = 85 mL
  • Molarity of diluted solution (M₂) =?

<h3>How to determine the molarity of the diluted solution </h3>

M₁V₁ = M₂V₂

6 × 25 = M₂ × 85

150 = M₂ × 85

Divide both side by 85

M₂ = 150 / 85

M₂ = 1.76 M

Thus, the concentration of the diluted solution is 1.76 M

Learn more about dilution:

brainly.com/question/15022582

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A hydrate of zinc nitrate has the formula Zn(NO3)2 . xH2O. If the mass of 1 mol of anhydrous zinc nitrate is 63.67% of the mass
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Be sure to answer all parts.
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(a) cesium bromide (CsBr): 9.15 grams

(b) calcium sulfate (CaSO4):  5.85 grams

(c) sodium phosphate (Na3PO4): 7.05 grams

(d) lithium dichromate (Li2Cr2O7):  9.88 grams

(e) potassium oxalate (K2C2O4):   7.15 grams

Explanation:

<u>(a) cesium bromide (CsBr):</u>

Molar mass of CsBR = 212.81 g/mol

Number of moles = molarity * volume

Number of moles = 0.100 M *0.43 L

Number of moles = 0.043 moles

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Molar mass of CaSO4 = 136.14 g/mol

Mass of CaSO4 required = moles * Molar mass

Mass of CaSO4 required = 0.043 moles * 136.14 g/mol

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<u>(c) sodium phosphate (Na3PO4):</u>

Molar mass of Na3PO4 = 163.94 g/mol

Mass of Na3PO4 required = moles * Molar mass

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<u>(d) lithium dichromate (Li2Cr2O7):</u>

Molar mass of Li2Cr2O7 = 229.87 g/mol

Mass of Li2Cr2O7 required = moles * Molar mass

Mass of Li2Cr2O7 required = 0.043 moles * 229.87 g/mol

Mass of Li2Cr2O7 required = 9.88 grams

<u>(e) potassium oxalate (K2C2O4):</u>

Molar mass of K2C2O4 = 166.22 g/mol

Mass of K2C2O4 required = moles * Molar mass

Mass of K2C2O4 required = 0.043 moles * 166.22 g/mol

Mass of K2C2O4 required = 7.15 grams

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