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DaniilM [7]
3 years ago
12

A 25.00-mL sample of 6.00 M HCl solution is diluted to a new volume of 85.00 mL. What is the concentration of the dilute solutio

n
Chemistry
1 answer:
natali 33 [55]3 years ago
6 0

The concentration of the dilute solution is 1.76 M

<h3>Data obtained from the question </h3>
  • Molarity of stock solution (M₁) = 6 M
  • Volume of stock solution (V₁) = 25 mL
  • Volume of diluted solution (V₂) = 85 mL
  • Molarity of diluted solution (M₂) =?

<h3>How to determine the molarity of the diluted solution </h3>

M₁V₁ = M₂V₂

6 × 25 = M₂ × 85

150 = M₂ × 85

Divide both side by 85

M₂ = 150 / 85

M₂ = 1.76 M

Thus, the concentration of the diluted solution is 1.76 M

Learn more about dilution:

brainly.com/question/15022582

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What is the volume of the rock in the image in mL
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How many grams of FeCo3 will be produced from 57.2g FeCl2
Evgesh-ka [11]

Answer:

             287.30 g of FeCO₃

Solution:

The Balance Chemical Equation is as follow,

                           FeCl₂ + Na₂CO₃    →    FeCO₃ + 2 NaCl

Step 1: Calculate Mass of FeCl₂ as,

                            Molarity  =  Moles ÷ Volume

Solving for Moles,

                            Moles  =  Molarity × Volume

Putting Values,

                            Moles  =  2 mol.L⁻¹ × 1.24 L

                           Moles  =  2.48 mol

Also,

                            Moles  =  Mass ÷ M.Mass

Solving for Mass,

                            Mass  =  Moles × M.Mass

Putting Values,

                            Mass  =  2.48 mol × 126.75 g.mol⁻¹

                            Mass =  314.34 g of FeCl₂

Step 2: Calculate Mass of FeCO₃ formed as,

According to equation,

          126.75 g (1 mole) FeCl₂ produces  =  115.85 g (1 mole) FeCO₃

So,

               314.34 g of FeCl₂ will produce  =  X g of FeCO₃

Solving for X,

                     X =  (314.34 g × 115.85 g) ÷ 126.75 g

                     X =  287.30 g of FeCO₃

<h2>brainlyest pleas</h2>
4 0
2 years ago
A 46.9 gram sample of a substance has a volume of about 3.5 centimeters3. It is solid at a room temperature of 23ºC. Out of the
Masteriza [31]

Answer:- C. Hafnium.

Solution:- Mass of the sample is 46.0 g and it's volume is 3.5cm^3 .

From mass and volume, we can calculate it's density using the formula:

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density=\frac{46.9g}{3.5cm^3}

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On the basis of the density, this substance could either be mercury or hafnium. Since the substance is a solid at room temperature where as mercury is liquid. So, it can't be mercury.

The right choice is C) Hafnium.

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3 years ago
Could some some one help with 2 4 5 7 8​
sesenic [268]

Answer:

For number 2, your answer is C.

Explanation:

The nucleus is positively charged because the proton is positive and a neutron is neutral. An electron has a negative charge.

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