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3 years ago

Are the particles in a solid in constant motion, or are they "frozen in place?"

Chemistry

2 answers:

babymother [125]3 years ago

4 0

Particles that are in a solid are tightly locked in place so the answer to your question would be "Frozen in place"

Tems11 [23]3 years ago

3 0

The molecules are frozen in place but still vibrate

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The coiling of the protein chain backbone into an alpha helix (like a spring) is referred to as the ________.

Agata [3.3K]

Answer: secondary structure

Explanation:

5 0

3 years ago

Calculate: A. Mercury has a specific Heat Capacity of 0.14 J/goC. How much heat is needed to raise the thermometer temperature 1

kari74 [83]

Answer:

$\boxed {\boxed {\sf 56 \ Joules}}$

Explanation:

We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

$q=mc \Delta T$

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.

ΔT= final temperature - initial temperature
ΔT= 95°C - 15°C = 80°C

We know the variables and can substitute them into the formula.

$m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C$

$q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)$

Multiply the first numbers. The grams will cancel.

$q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )$

Multiply again. This time the degrees Celsius cancel.

$q= 56 \ J$

56 Joules of heat are needed.

4 0

3 years ago

How many moles are contained in a 4.67-l sample of gas at 30°c and 199 kpa?

ohaa [14]

Pv=nRT
where,p=199, R(constant)=8.314, V=4.67 T=30C=293K
n=pv/RT=0.38 moles

4 0

3 years ago

Read 2 more answers

No explanation needed just answer pls. quick.

luda_lava [24]

Answer: The answer is C in ionic bonds electrons are transferred and in covalent bonds they are shared

4 0

2 years ago

If 12.8 g of CaCO3 decomposes at 38 degrees C and 0.96 atm, how many dm3 of CO2 are formed in addition to CaO? CaCO3 → CaO + CO2

jasenka [17]

Answer:

3.4dm3

Explanation:

We'll begin by calculating the number of mole of CaCO3 present in 12.8g of CaCO3.

This can be achieved as shown below:

Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol

Mass of CaCO3 obtained from the question = 12.8g

Number of mole of CaCO3 =?

Number of mole = Mass /Molar Mass

Number of mole of CaCO3 = 12.8/100

Number of mole of CaCO3 = 0.128 mole

The equation for the reaction is given below:

CaCO3 → CaO + CO2

From the equation above,

1 mole of CaCO3 produced 1 mole of CO2.

Therefore, 0.128 mole of CaCO3 will also produce 0.128 mole of CO2.

Now, we can obtain the volume of CO2 produced as follow:

Data obtained from the question include:

T (temperature) = 38°C = 38 + 273 = 311K

P (pressure) = 0.96 atm

n (number of mole of CO2) = 0.128 mole

R (gas constant) = 0.082atm.dm3/Kmol

V (volume of CO2) =?

Using the ideal gas equation PV = nRT, the volume of CO2 produced can be obtained as shown:

PV = nRT

0.96 x V = 0.128 x 0.082 x 311

Divide both side by 0.96

V = (0.128 x 0.082 x 311) /0.96

V = 3.4dm3

Therefore, 3.4dm3 of CO2 are produced.

7 0

3 years ago