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ale4655 [162]
3 years ago
14

What two units of measure are necessary for describing speed

Physics
1 answer:
Shtirlitz [24]3 years ago
8 0
Distance and time, distance because that's how far and time because that's how long
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What rapid changes to earths surface are caused by shifting plates
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I am not sure if this is the answer you are looking for but a earthquake occurs when the plates shift. 
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3 years ago
A mass hanged on a spring scale. what is the force exerted by gravity on 700g ?
Ipatiy [6.2K]

Answer:

6.86 N

Explanation:

Applying,

F = mg............... Equation 1

Where F = Force exerted by gravity on the mass, m = mass, g = acceleration due to gravity

Note: The Force exerted by gravity on the mass is thesame as the weight of the body.

From the question,

Given: m = 700 g = (700/1000) = 0.7 kg

Constant: g = 9.8 m/s²

Substitute these values into equation 1

F = 9.8(0.7)

F = 6.86 N

6 0
2 years ago
Assuming that the circuit is in the steady state, what is the total energy stored in the two capacitors? j
Neporo4naja [7]

<span>The total energy stored is the sum of the energy stored in the capacitors. If the capacitors  are series connected capacitors, then the charging current is the same for both capacitors. This means that each capacitor stores the same energy and the stored energy is two times the energy of any of the capacitors.</span>





8 0
3 years ago
While running around the track at school, Milt notices that he runs due East on the 100m homestretch and due West on the 100m ba
Yuri [45]
Answer a would be correct since velocity is a vector and has a magnitude and a direction. In this case v₁ = - v₂.
8 0
3 years ago
Read 2 more answers
A 20.0 kg crate sits at rest at the bottom of a 15.0-m-long ramp that is inclined at 34.0° above horizontal. A constant horizont
ankoles [38]

Answer:

987 joules, 3.01s

Explanation:

(A)

from the attached diagram

net force, Fnet, pulling the crate up the ramp is given by

Fnet = FcosФ - WsinФ - Fr

where FcosФ is the component of horizontal force 290N resolved parallel to the plane

WsinФ = mgsinФ = component of the weight of the crate resolved parallel to the plane

Fr = constant opposing frictional force

Fnet = 290cos34⁰ - 20 × 9.8 × sin34° - 65

Fnet = 240.421 - 109.602 - 65

Fnet = 65.82N

Work done on the crate up the ramp, W, is given by

W = Fnet × d (distance up the plane)

W = 65.819 × 15

W = 987.285 joules

W = 987 joules (to 3 significant Figures)

(B)

to calculate the time of travel up the ramp

we use the equation of motion

s = ut + \frac{1}{2}at^{2}

where s = distance up the plane, 15m

u = Initial velocity of the crate, which is 0 for a body that is initially at rest

a = acceleration up the plane, given by

a = \frac{Fnet}{m}

where m = mass of the crate, 20 kg

now, a = \frac{65.819}{20} \\a = 3.291\frac{m^{2} }{s}

from, s = ut + \frac{1}{2}at^{2}

15 = 0*t + \frac{1}{2}* 3.291 * t^{2}

15 = 0 + 1.645t^{2}

15 = 1.645t^{2}

t = \sqrt{\frac{15}{1.645} }

t = 3.019

t = 3.01s (to 3 sig fig)

7 0
3 years ago
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