Answer:
B. Lower than 100 °C because hydrogen sulfide has dipole-dipole interactions instead of hydrogen bonding.
Explanation:
Boiling point is a physical property which is usually a product of breaking intermolecular bonds.
Both dipole-dipole attractions are intermolecular bonds and they have serious effect on boiling point of a substance.
Hydrogen bonds are very strong intermolecular bonds compared to dipole-dipole attractions. In hydrogen bonding hydrogen atom is directly joined to a highly electronegative atom.
Dipole-Dipole attraction exists between molcules that are polar. Such molecules line up such that the positive pole of one molecule attracts the negative pole of another.
Hydrogen bonds in water are much stronger than the dipole-dipole attraction of hydrogen sulfide.
Answer:
1-b
2-weaker(option is incorrect)
3-a
Explanation:
1-b because iodine is more electronegative because of this negative on iodine will be more stable as negative charge on more electronegative element is more stable.
2-weaker as size of Te (Tellurium) is greater than S (sulphur) so bond length of H-Te is larger than H-S and therefore bond energy will be lesser and can easily give hydrogen in case of H-Te. as bond energy is inversly proportional to bond length.
3-a hydrogen has more negative electron affinity so hydrogen will have -1 charge and it will behave as a electron donar atom that is basic not acidic hence NaH is not acidic.
