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saw5 [17]
3 years ago
13

Copper has a specific heat of 0,900 J(g C). How much energy in kJ is needed to raise the temperature of a 700 g block of aluminu

m from 30.7°C to 82,1C?(show your steps)
Chemistry
1 answer:
sashaice [31]3 years ago
4 0

Answer:

32.4 kJ

Explanation:

Given that:

Specific heat capacity fo copper, c = 0.9

Mass of copper, m = 700 g

Temperature change, dθ ;t2 - t1 = (82.1 - 30.7) = 51.4

Energy required, E = mcdθ

E = 700 * 0.9 * 51.4

E = 32382 J

Energy required on kJ

32382 / 1000

= 32.382 kJ

= 32.4 kJ

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Uranium (VIII) Sulfide formula
tresset_1 [31]

Answer:

US₂

Explanation:

Uranium sulfide (US₂)

Uranium atomic symbol = U

Sulfur atomic symbol = S

Uranium valency = +4

Sulfur valency = -2

So;

Uranium sulfide (US₂)

8 0
3 years ago
What are the very small particles that make up all matter?
nadezda [96]
All matter is made up of particles called atoms and molecules (as opposed to being continuous or just including particles). On the following page, the idea is stated as one of four concepts in Dalton's theory: “All matter is composed of tiny, indivisible particles called atoms” (p. 158s).
3 0
2 years ago
How many liters of O2 at 298 K and 1.00 bar are produced in 1.50 hr in an electrolytic cell operating at a current of 0.0200 A?
stellarik [79]

Answer: 0.0069L

Explanation:

2H2O(l) ---->O2(g) + 4H+(aq) + 4e-

no of moles= it/eF

NO of moles of O2 produced = (Current in Ampere x Time in second)/ (Faraday constant x Number of electrons required)

Moles of O2 produced = (0.02x (60 x 60X1.5 s)/(96485 x 4)

= 0.0002798 moles= 2.798x 10 ^-4moles

Using  ideal gas equation,

P V = n R T

Where, P is the pressure,

V is the volume,

n is the number of moles,

R is the gas constant, and T is the temperature

We have, 1 bar = 0.986923 atm

Substituting the values,

V = nRT/P = (2.798 x 10-4moles x 0.08205 L atm mol K x 298 K)/ 0.986923 atm = 0.0069L

Volume of O2 produced = 0.0069L

7 0
3 years ago
a doctor's order is 0.125 g of ampicillin. the liquid suspension on hand contains 250 mg/5.0 ml. how many milliliters of the sus
disa [49]
0.125 g=(0.125 g)(1000 mg/1g)=125 mg.

Then, we need 125 mg of ampicillin.
5 ml of  liquid suspension contains 250 mg of ampicilling , therefore:

5 ml----------------250 mg of ampicilling
x--------------------125 mg of ampicilling

x=(5 ml * 125 mg of ampicilling) / 250 mg of ampicilling=2.5 ml

Answer: we require 2.5 ml
5 0
3 years ago
Read 2 more answers
Energy is transferred
Andrei [34K]
True is the right oneee
6 0
2 years ago
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