Answer:
.562 mol (with respect to signifigant figures)
Explanation:
to find moles we must use concentration to cancel liters.
2.250 mol/L x .250 L = .5625 mol
An alligator has has an extra eyelid that protects there eyes underwater. It's basically their own built-in goggles.
Answer:
a. 473mL.
b. 79.38kg
c. 24.47lb of fat
d. 42.5g of N.
Explanation:
a. A qt is equal to 946mL. 0.500qt are:
0.500qt * (946mL / 1qt) = 473mL
b. 1lb is equal to 0.4536kg, 175lb are:
175lb *(0.4536kg / 1lb) = 79.38kg
c. The fat in kg of the athlete is:
74kg * 15% = 11.1kg of fat. In pounds:
11.1kg * (1lb / 0.4536kg) = 24.47lb of fat
d. The mass of nitrogen in the fertilizer is:
10.0oz * 15% = 1.5oz of N
1 oz is equal to 28.35g. 1.5oz are:
1.5oz * (28.35g / 1oz) = 42.5g of N
The mass of 
that would be formed will be 18.22 grams
<h3>Stoichiometric calculations</h3>
Let us first look at the balanced equation of the reaction:
The mole ratio of Y to 
is 2:3.
Mole of 10.0 grams of Y = 10/88.9 = 0.11 moles
Mole of 10.0 grams = 10/71 = 0.14 moles
3/2 of 0.11 = 0.165. Thus, is limiting in availability.
Mole ratio of and = 3:2
Equivalent mole of = 2/3 x 0.14 = 0.093 moles.
Mass of 0.093 moles =0.093 x 195.26 = 18.22 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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Answer:
18 molecules of ATP will be produced for the breakdown of methionine to succinyl CoA and the entry of succinyl CoA to the citric acid cycle with no input of glucose.
Explanation:
Reactions reduced co enzymes ATP formation
α keto glutarate to propionyl CoA 2 NADH 6 moles
Succinyl CoA to succinate 2 GTP≈ 2 ATP
Succinate to fumarate 2FADH2 4 moles
Malate to oxaloacetate 2 NADH 6 moles
