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OleMash [197]
3 years ago
10

If an electromagnetic wave from crest to crest measured 30 nanometers what kind of wave would it be

Physics
1 answer:
KIM [24]3 years ago
7 0
Well, I recognize them by frequency, so let's see . . .

Frequency = (speed) / (wavelength)

Speed = around 3 x 10⁸ m/s in vacuum

Frequency = (3 x 10⁸ m/s) / (30 x 10⁻⁹ m) = 1 x 10¹⁶ Hz.

That's a frequency I don't recognize,
so I gotta go lookit up.

30 nanometers is a hard hard X-ray.
At 10¹⁹ Hz . . . 1,000 times higher freq/shorter wavelength . . .
it would be considered a gamma ray.  But this one is just a
hard, hard X-ray. 
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Why is the perfect mechine is not possible in the real life?​
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3 years ago
We wrap a light, nonstretching cable around a 8.00 kg solid cylinder with diameter of 30.0 cm. The cylinder rotates with negligi
antoniya [11.8K]

Answer:

h = 16.67m

Explanation:

If the kinetic energy of the cylinder is 510J:

Kc=510=1/2*Ic*\omega c^2

\omega c=\sqrt{510*2/Ic}

Where the inertia is given by:

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Replacing this value:

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Speed of the block will therefore be:

V_b=\omega_c*R_c=106.46*0.15=15.969m/s

By conservation of energy:

Eo = Ef

Eo = 0

Ef = 510+1/2*m_b*V_b^2-m_b*g*h

So,

0 = 510+1/2*m_b*V_b^2-m_b*g*h

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3 0
4 years ago
I need help with these. Please show workings<br>​
Sauron [17]

Answer:

Imp = 25 [kg*m/s]

v₂= 20 [m/s]

Explanation:

In order to solve these problems, we must use the principle of conservation of linear momentum or momentum.

1)

(m_{1}*v_{1})+(F*t)=(m_{1}*v_{2})

where:

m₁ = mass of the object = 5 [kg]

v₁ = initial velocity = 0 (initially at rest)

F = force = 5 [N]

t = time = 5 [s]

v₂ = velocity after the momentum [m/s]

(5*0) +(5*5) = (m_{1}*v_{2}) = Imp\\Imp = 25 [kg*m/s]

2)

(m_{1}*v_{1})+(F*t)=(m_{1}*v_{2})\\(0.075*0)+(30*0.05)=(0.075*v_{2})\\v_{2}=20 [m/s]

8 0
3 years ago
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