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igomit [66]
4 years ago
4

Which two technologies use the same range of radio wave frequencies? television broadcasting and AM radio broadcasting cell phon

es and space communication CB radios and submarine communication AM and FM radio broadcasting
Physics
2 answers:
KiRa [710]4 years ago
8 0

Cellphones, some space communication, and also GPS all operate roughly in the same region of the telecommunications spectrum.

Shtirlitz [24]4 years ago
7 0

Answer:

cell phones and space communication

Explanation:

All the communication part via radio, television and cell phones etc is done with the help of Electromagnetic waves.

Since electromagnetic waves do not requires any medium as well as they can travel at speed of light so this is the fastest mode of communication.

We can use the electromagnetic waves of different frequency for different type of usage.

Here for same frequency range is used while we use it in form of cell phone usage of space communication usage.

This is because in above part of usage the frequency range will satisfy the conditions for both either cell phone or for space communication.

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Which of the following describes the moon’s motion around Earth?
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Answer:

i think B?

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A car accelerates at a rate of 3 m/s^2. If it's original speed is 8 m/s, how many seconds will it take the car to reach a final
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26-8/3 = 6 seconds
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What is specific heat?
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Specific heat, ratio of the quantity of heat required to raise the temperature of a body one degree to that required to raise the temperature of an equal mass of water one degree.
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In the metaphor of the bottle for theory of constraints, which part of the bottle represents the constraint?
SpyIntel [72]

In the metaphor of the bottle for theory of constraints, the part of the bottle represents the constraint is neck.

<h3>What is metaphor?</h3>

A metaphor is a figure of the speech that describes an object or action in a way that isn’t literally true, but helps explain an idea or make a comparison.

Here are the basics:

A metaphor states that one thing is the another thing. It equates those two things not because they actually are the same, but for the sake of comparison or symbolism and if you take a metaphor literally, it will probably sound very strange (are there actually any sheep, black or otherwise, in your family?). Metaphors are used in the poetry, literature, and anytime someone wants to add some color to their language

The uses of metaphor, and the official definition:

A word or phrase for one thing that is used to refer to the another thing in order to show or suggest that they are similar

An object, activity, or idea that is used as a symbol of the something else

Metaphors are a form of the figurative language, which refers to words or expressions that mean something different from their literal definition. In the case of metaphors, literal interpretation would often be pretty silly.

To know more about phrase visit: brainly.com/question/24271343

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5 0
1 year ago
Read 2 more answers
The noble gases neon (atomic mass 20.1797 u) and krypton (atomic mass 83.798 u) are accidentally mixed in a vessel that has a te
vagabundo [1.1K]

Answer:

(a) Kav Ne = Kav Kr = 7.29x10⁻²¹J

(b) v(rms) Ne= 659.6m/s and v(rms) Kr= 323.7m/s

Explanation:

(a) According to the kinetic theory of gases the average kinetic energy of the gases can be calculated by:

K_{av} = \frac{3}{2}kT (1)        

<em>where K_{av}: is the kinetic energy, k: Boltzmann constant = 1.38x10⁻²³J/K, and T: is the temperature </em>

<u>From equation (1), we can calculate the</u><u> average kinetic energies for the krypton and the neon:</u>

K_{av} = \frac{3}{2} (1.38\cdot 10^{-23} \frac{J}{K})(352.2K) = 7.29\cdot 10^{-21}J  

(b) The rms speeds of the gases can be calculated by:

K_{av} = \frac{1}{2}mv_{rms}^{2} \rightarrow v_{rms} = \sqrt \frac{2K_{av}}{m}  

<em>where m: is the mass of the gases and v_{rms}: is the root mean square speed of the gases</em>

For the neon:

v_{rms} = \sqrt \frac{2(7.29 \cdot 10^{-21}J)}{20.1797 \frac{g}{mol} \cdot \frac {1mol}{6.022\cdot 10^{23}molecules} \cdot \frac{1kg}{1000g}} = 659.6 \frac{m}{s}          

For the krypton:

v_{rms} = \sqrt \frac{2(7.29 \cdot 10^{-21}J)}{83.798 \frac{g}{mol} \cdot \frac {1mol}{6.022\cdot 10^{23}molecules} \cdot \frac{1kg}{1000g}} = 323.7 \frac{m}{s}  

Have a nice day!

3 0
3 years ago
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