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Gemiola [76]
3 years ago
12

Which of the following describes the moon’s motion around Earth?

Physics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

i think B?

Explanation:

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An electron moving with a velocity v⃗ = 5.0 × 107 m/s i^ enters a region of space where perpendicular electric and a magnetic fi
stiv31 [10]

Answer:

Magnetic field, B=2\times 10^{-4}\ T

Explanation:

Given that,

Velocity of electron, v=5\times 10^7\ m/s

It enters  a region of space where perpendicular electric and a magnetic fields are present.

Magnitude of electric field, E=10^4\ V/m

We need to find the magnetic field will allow the electron to go through the region without being deflected.

Magnetic force on the electron, F_m=qvB\ sin\theta.......(1)

Electric force on the electron, F = q E........(2)

From equation (1) and (2) we get:

qvB\ sin\theta=qE

B=\dfrac{E}{v}

B=\dfrac{10^4\ V/m}{5\times 10^7\ m/s}

B = 0.0002 T

or

B=2\times 10^{-4}\ T

Hence, this is the required solution.

3 0
3 years ago
Please help I’ll give brainliest
lesya [120]

Answer:

Objects that have like charges attract each other.

Objects that have opposite charges repel each other.

When fur is rubbed on the balloon electrons move from the balloon to the fur.

This is because the balloon's material is an insulator.

Electrons have negative charge.

Protons have a positive charge.

neutrons have no charge.

Explanation:

4 0
3 years ago
What property is an acid-base indicator used to measure?
Volgvan

Answer:

ph

Explanation:

4 0
3 years ago
Read 2 more answers
The charge density of a uniformly charged disk 0.420 m in diameter is 2.92 ✕ 10−2 C/m2. What is the magnitude of the electric fi
iragen [17]

Answer:

E = {(Charge Density/2e0)*(1 - [z/(sqrt(z^2 - R^2))]}

R is radius = Diameter/2 = 0.210m.

At z = 0.2m,

Put z = 0.2m, and charge density = 2.92 x 10^-2C/m2, and constant value e0 in the equation,

E can be calculated at distance 0.2m away from the centre of the disk.

Put z = 0.3m and all other values in the equation,

E can be calculated at distance 0.3m away from the centre of the disk

3 0
3 years ago
On a farm, you are pushing on a stubborn pig with a constant horizontal force with magnitude 30.0 n and direction 37.0° counterc
sashaice [31]

<span>Since the force is applied at an angle from the horizontal, we will use the horizontal component of this force in calculating for the displacements.
From derivation, the Fx is:</span>

Fx = F cos φ

Where:

Fx = is the horizontal component of the force

F = total force

φ = angle in radian = 37 * pi / 180 = 0.645 rad

Calculating: Fx = 30.0 N * cos(0.645)

Fx = 23.97 N = 24 N

Calculating for Work: W = Fx * d

A. W = 24 N * 15 m = 360 N

B. W = 24 N * 16 m = 384 N

C. W = 24 N * 12 m = 288 N

D. W = 24 N * 14 m = 336 N 

8 0
3 years ago
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