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Softa [21]
2 years ago
7

Guys please someone help In the middle of a test HELP ASAP

Mathematics
1 answer:
Ket [755]2 years ago
5 0

Answer:

2 hour 35 minutes and 56 seconds

Step-by-step explanation:

I am looking at you

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What is the volume of the triangular prism shown below?
liberstina [14]

Answer:

B

Step-by-step explanation:

The volume (V) of the triangular prism is calculated as

V = area of triangular face × length

Area of triangle = \frac{1}{2} bh ( b is the base and h the height )

Here b = 6 and h = 8, thus

Area = \frac{1}{2} × 6 × 8 = 3 × 8 = 24 units², thus

V = 24 × 20 = 480 units³ → B

8 0
3 years ago
Is there anybody who can help me with this question?please
Butoxors [25]

Answer:

the people would save 12 meters

Step-by-step explanation:

If it is a right triangle that has 45,45,90 angles, Than two side lengths would be the same, so there are two 30 meter side lengths. The path is 48 meters long, and the road would be 60 meters long (30+30), so you subtract 48 from 60, and get 12. You would save 12 meters

8 0
3 years ago
A basketball player's total points scored for the season went from 158 to 231 over a period of 5 games. What was his scoring rat
Len [333]

Answer:

14.6

Step-by-step explanation:

(231 - 158) / 5 = 14.6

6 0
3 years ago
Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams
hram777 [196]

Answer:

X(16)=25.71grams

Step-by-step explanation:

let X(t) denote grams of C formed in  t mins.

For X grams of C we have:

\frac{2}{3}Xg of A and \frac{1}{3}Xg of B

Amounts of A,B remaining at any given time is expressed as:

40-\frac{2}{3}Xg of A and  50-\frac{1}{3}Xg  of B

Rate at which C is formed satisfies:

\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt  \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}

Apply the initial condition,X(0)=0 ,to the expression above

0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}

Now at X(8)=15:

15=90-\frac{90}{90\times 8k+1}  \ ->75=\frac{90}{720k+1}\\k=0.0002778

Substitute  in X(t) to get

X(t)=90-\frac{90}{0.0002778t\times 90+1}\\X(t)=90-\frac{90}{0.25t+1}\\But \ t=16\\\therefore X(t)=90-\frac{90}{0.025\times16+1}\\X(t)=25.71

5 0
2 years ago
Plz help quick!!!!!!!!!!!!!!!!!!!!!!!
4vir4ik [10]

Answer:

Step-by-step explanation:

well... all the least common factor have to write in the increasing order.

So, following this picture, we have to write in this order:

2 x 2 x 2 x 3 x 5

5 0
2 years ago
Read 2 more answers
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