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2 years ago

6

PLEASE GELP ME I WILL MARK BRAINLIEST

1 answer:

klio [65]2 years ago

4 0

4Li + O₂ ⇒ 2Li₂O

Li₂O = 2/4 x 3.33 = 1.665

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Write four facts of cross breeding plants

Valentin [98]

Answer:

Plant breeding

Plant breeding is the science of changing the traits of plants in order to produce desired characteristics. It has been used to improve the quality of nutrition in products for humans and animals.

Explanation:

5 0

3 years ago

What is the [H+] of a solution with a pH of 5.6

lisabon 2012 [21]

Answer:

Hi there!

The answer to this question is 2.5118X10^-6

Explanation:

The formula to solve this is 10^-pH

5 0

3 years ago

If the titration of h2po4− in a urine sample was continued until all of the acid in the solution was neutralized, how many equiv

sergiy2304 [10]

Two equivalents of NaOH are needed to fully neutralize the solution.

<h3>What is a neutralization reaction?</h3>

A neutralization reaction involves the reaction of an acid and a base to form salt and water. The reaction is exothermic in nature.

For example,

$HCl (aq) + NaOH(aq)\rightarrow NaCl(aq) + H_2O (l)$

During the titration of $H_2PO_4^-$ it gives $2H^+$ .

$H_2PO_4^- \rightarrow 2H^+ +PO_4^3^-$

To neutralize these $2H^+$ , 2 $OH^-$ is needed which come from 2 equivalents of NaOH

$2NaOH \rightarrow2 Na^+ +2OH^-$

Therefore, 2 equivalents of NaOH are needed

Learn more about neutralization reaction:

brainly.com/question/23008798

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5 0

2 years ago

Me when me when me when me when me when

Bad White [126]

This is so true, so facts

3 0

2 years ago

Read 2 more answers

In a student experiment, a constant-volume gas thermometer is calibrated in liquid nitrogen (−196°c ) and in boiling ethyl alcoh

larisa86 [58]

The given linear equation is:

$P=a+bt$

Determine the value of a and b (constants) by plug in the values of pressure and temperature.

$P_{1}$ (Pressure of liquid nitrogen) = $0.349 atm$

$T_{1}$ (Temperature of liquid nitrogen) = $-196^{0}C$

$P_{2}$ (Pressure of ethyl alcohol) = $1.634 atm$

$T_{2}$ (Temperature of ethyl alcohol) = $77^{0}C$

Put above values in given equation:

$P_{1}=a+bT_{1}$

$0.349 atm=a+b(-196^{0}C)$ (1)

$P_{2}=a+bT_{2}$

$1.634 atm=a+b(77^{0}C)$ (2)

Subtract equation (1) from equation (2), we get the value of b

$1.285 atm = b(273^{0}C)$

$b = 4.7\times 10^{-3} atm/^{0}C$

Now, put the value of b in equation (1)

$0.349 atm=a+(4.7\times 10^{-3}atm/^{0}C)(-196^{0}C)$

$a = (0.349) + (4.7\times 10^{-3}atm/^{0}C)(196^{0}C)$

$a =921.549\times 10^{-3} atm$

Now, at absolute zero, Pressure is equal to zero.

Absolute temperature = $T_{o} =-\frac{a}{b}$

$T_{o} = -\frac{921.549\times 10^{-3} atm}{4.7\times 10^{-3} atm/^{0}C}$

= $-196.074 ^{0}C$

Thus, absolute zero = $-196.074 ^{0}C$

8 0

3 years ago