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In the Energy and Specific Heat lab, you measure the temperature change of water to study the specific heat of a metal. What sta

pshichka [43]

The question is incomplete, the complete question is;

In the Energy and Specific Heat lab, you measure the temperature change of water to study the specific heat of a metal. What statement explains the relationship between the water and the metal you are studying? Select one: O The heat lost by the metal plus the heat gained by the water equals 100. O The temperature change of the metal is equal to the temperature change of the water. O The heat lost by the metal is equal to the heat gained by the water. The initial temperature of the metal equals the initial temperature of the water

Answer:

The heat lost by the metal is equal to the heat gained by the water.

Explanation:

When the piece of metal is put into water, heat is lost by the metal and gained by the water.

Recall that energy is conserved hence heat lost by metal must be equal to heat gained by water.

Thus, the relationship between the metal under study and the water is that the metal looses heat to the water and heat lost by metal is equal to heat gained by water.

3 0

3 years ago

Most plastics are made from oil or natural gas. One step in making plastics from these resources is called cracking. Cracking is

kramer

Answer:

true im pretty sure

Explanation:

6 0

3 years ago

What is the percent-by-mass, %(m/m), concentration of sucrose ( table sugar) in a solution made by dissolving 22.8 g of sucrose

Ede4ka [16]

Answer:

32.6 %

Explanation:

Given data

Mass of sucrose (solute): 22.8 grams

Mass of water (solvent): 47.1 grams

Step 1: Calculate the mass of the solution

The mass of the solution is equal to the sum of the mass of the solute and the mass of the solvent.

m(solution) = m(solute) + m(solvent)

m(solution) = 22.8 g + 47.1 g

m(solution) = 69.9 g

Step 2: Calculate the percent-by-mass of sucrose in the solution

We will use the following expression.

$\% m/m = \frac{mass\ of\ sucrose}{mass\ of\ solution} \times 100\% = \frac{22.8g}{69.9g} \times 100\% = 32.6 \%$

5 0

3 years ago

Read 2 more answers

Guy’s pleaseeee help

dusya [7]

Answer:

A. All isotopes have no charge

5 0

3 years ago

Determine the packing efficiency of a simple cubic unit cell that contains one atom with a metallic radius of 175 pm.

PilotLPTM [1.2K]

Answer:

the packing efficiency is 52.36%

Explanation:

Given the data in the question;

simple cubic unit cell that contains one atom with a metallic radius of 175 pm;

we know that;

Edge length of Simple cubic (a) is related to radius of atom (r) as follows;

a = 2r

since radius r = 175 pm

we substitute

a = 2 × 175 pm

a = 350 pm

Now we get the volume unit;

Volume of unit cell = a³ = ( 350 pm ) = 42875000 pm³

Next we get Volume of sphere;

Volume of Sphere = $\frac{4}{3}$ πr³

Volume occupied by 1 atom = $\frac{4}{3}$ × π × ( 175 pm )³

= $\frac{4}{3}$ × π × 5359375 pm³

= 22449297.5 pm³

Now, the packing efficiency = ( Volume occupied by 1 atom / Volume of unit cell ) × 100

we substitute;

packing efficiency = ( 22449297.5 pm³ / 42875000 pm³ ) × 100

= 0.523598 × 100

= 52.36%

Therefore, the packing efficiency is 52.36%

8 0

3 years ago