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Monica [59]
1 year ago
14

A "phaser" blast form the starship "ENTERPRISE" sends out a

Physics
1 answer:
Iteru [2.4K]1 year ago
5 0

The frequency of the light beam is 4.72 x 10¹⁴ Hz.

<h3>Frequency of the light beam</h3>

The frequency of light beam and wavelength of light is related in the following equations;

c = fλ

where;

  • c is the speed of light = 3 x 10⁸ m/s
  • f is the frequency
  • λ is the wavelength

f = c/λ

f = (3 x 10⁸) / (636 x 10⁻⁹)

f = 4.72 x 10¹⁴ Hz

Thus, the frequency of the light beam is 4.72 x 10¹⁴ Hz.

Learn more about frequency of light beams here: brainly.com/question/14295752

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A tank is filled with an ideal gas at 400 K and pressure of 1.00 atm.
bekas [8.4K]

To find the temperature it is necessary to use the expression and concepts related to the ideal gas law.

Mathematically it can be defined as

PV=nRT

Where

P = Pressure

V = Volume

n = Number of moles

R = Gas constant

T = Temperature

When the number of moles and volume is constant then the expression can be written as

\frac{P_1}{T_1}=\frac{P_2}{T_2}

Or in practical terms for this exercise depending on the final temperature:

T_2 = \frac{P_2T_1}{P_1}

Our values are given as

T_1 = 400K\\P_1 = 1atm\\P_2 = 2atm

Replacing

T_2 = \frac{(2)(400)}{1}\\T_2 = 800K

Therefore the final temperature of the gas is 800K

6 0
2 years ago
The figure shows two springs (k1 = 10 N/m and k2 = 20 N/m ) attached to a block that can slide on a frictionless surface. In the
Rainbow [258]

Answer:

Explanation:

a )

Energy stored by left spring when compressed = 1/2 k x²

= .5 x 10 x .02² = .002 J .

Let compression in right spring = y

energy stored to right spring = 1/2 k y²

1/2 k y² = 0.002

.5 x 20 x y² = 0.002

y = .01414 m

= 1.4  cm

7 0
2 years ago
when a circular plate of metal is heated in an oven, its radius increases at .03 cm/min, at what rate is the area increasing whe
Alinara [238K]

Answer:

Rate of change of area will be 9.796cm^2/min

Explanation:

We have given rate of change of radius \frac{dr}{dt}=0.03cm/min

Radius of the circular plate r = 52 cm

Area is given by A=\pi r^2

So \frac{dA}{dt}=2\pi r\frac{dr}{dt}

Puting the value of r and \frac{dr}{dt}

\frac{dA}{dt}=2\times 3.14\times 52\times 0.03=9.796cm^2/min

So rate of change of area will be 9.796cm^2/min

6 0
3 years ago
It is easier to climb up a slanted slope than a vertical slope
V125BC [204]

IT IS EASIER TO CLIMB A SLANTED SLOPE

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2 years ago
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What is the displacement of an object during a specific unit of time?
azamat
Speed = distance / time
3 0
3 years ago
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