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solniwko [45]
2 years ago
12

Plsssssss can someone help me

Mathematics
2 answers:
FinnZ [79.3K]2 years ago
8 0

Answer: 2*2*2 = 8 13 could be the answer to  

Step-by-step explanation: 16 - 8 = 8

8 / 2 = 4

4 + 9 = 13

77julia77 [94]2 years ago
5 0

Answer:

2^3 = 8

Step-by-step explanation:

2*2*2 = 8

16 - 8 = 8

8 / 2 = 4

4 + 9 = 13

13 may be your answer

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What is the correct answer. what is the focus point of a parabola with this equation? y=1/8(x^2-4x-12)
anastassius [24]

The answer is C. (2,-2) u just search it up online and there are million answers

5 0
3 years ago
Read 2 more answers
Write the slope - intercept form of the equation of each line through the points -2,5) and (0,-2)​
grin007 [14]
Gradient (m) = change in y/change in x
-2-5/0–2 = 3.5
gradient (m) = 3.5
Now evaluate one of the coordinates and the gradient in the equation
y = mx + c
-2 = 3.5(0) + c
c = -2
so the answer is
y = 3.5x -2
3 0
2 years ago
Se necesita comprar 85 saleros para su restaurante. Si los saleros vienen empacados en presentaciones de 2,3 y 5 unidades, cual
Pepsi [2]

Responder:

5

Explicación paso a paso:

Dado que:

Número requerido de compra = 85

Unidades de paquete disponibles = 2, 3, 5

En su para comprar la cantidad exacta 85 de Saleros; la unidad de paquete a elegir debe ser;

Uno que es un factor de 85

Factores de 85: 1, 5, 17 y 85.

Por lo tanto, de las unidades de paquete disponibles disponibles, solo 5 es un factor de 85 y, por lo tanto, dará el número exacto de saleros necesarios.

3 0
3 years ago
A plane can fly 540 miles with the wind in one hour less than it can fly 480 miles against the wind. The average wind speed is 3
Bess [88]

Answer:

The speed of the plane in still air = 150 mph

Step-by-step explanation:

This is a relative velocity question

Let the velocity of the plane in still air be v

And let the time the plane can fly 480 miles against the wind be t

(Velocity of the plane relative to the wind) = (velocity of plane) - (velocity of wind)

Flying against the wind

(Velocity of plane relative to the wind) = (480/t)

(Velocity of the plane) = v

(Velocity of the wind) = 30 mph

(480/t) = v - 30

t = 480/(v-30) (eqn 1)

Flying with the wind

(Velocity of plane relative to the wind) = 540/(t-1)

(Velocity of the plane) = v

(Velocity of the wind) = -30 mph

540/(t - 1) = v + 30

t - 1 = 540/(v+30) (eqn 2)

Since t is equal in both cases, substitute the value of t in eqn 1 into eqn 2.

[480/(v-30)] - 1 = [540/(v+30)]

Multiply through by (v+30)(v-30)

480(v+30) - [(v+30)(v-30)] = 540(v-30)

480v + 14400 - (v² - 900) = 540v - 16200

480v + 14400 - v² + 900 = 540v - 16200

v² + 540v - 480v - 16200 - 14400 - 900 = 0

v² + 60v - 31500 = 0

Solving the quadratic equation,

v = 150 mph or v = -210 mph

We'll pick the positive answer because of the directions we have established.

Therefore, the speed of the plane in still air = 150 mph

Hope this Helps!!!

3 0
2 years ago
Please help will give Brianliest!!!
marshall27 [118]

Answer: y=2(x-3)-5

I hope this is good enough:

8 0
3 years ago
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