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elena55 [62]
3 years ago
11

What is meaning of charge?​

Physics
2 answers:
Phoenix [80]3 years ago
7 0

Explanation:

A basic property of electrons, protons, and other subatomic particles that help them to experience a force when placed in an electric field.

Hope it helps you.

Stay safe, stay healthy and blessed.

Good luck for ur exams.

Have a great day !

Thank you

ludmilkaskok [199]3 years ago
3 0

Answer:

demand (an amount) as a price for a service rendered or goods supplied.

Explanation:

to enter or record as an obligation against a person or his account.  to accuse or impute a fault to (a person, etc), as formally in a court of law. to command; place a burden upon or assign responsibility toI was charged to take the message to headquarters.

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In this image F1 is equal to 100 N and F2 is equal to 50 N. What is the net force?
ZanzabumX [31]

Answer:

net force would be 50 N right

Explanation:

6 0
2 years ago
How does a mathematical model help you understand the science concepts? Give an example.
sveta [45]
Usually describes a system by a set of variables in a set of equations established relationships between the variables and variables maybe of many types real or integer numbers Boolean values of strings for example
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3 years ago
Select all the correct answers. a leaf falls through the air, floating as it falls. air resistance is visibly affecting the leaf
musickatia [10]

Surface area and Mass

When a leaf falls, it is being accelerated by gravity to the ground but opposed by air resistance also the drag. The net force on a leaf will therefore be calculated by subtracting its weight of the leaf from its drag.

<h3>What is Air resistance ?</h3>

Air exerts a force known as air resistance. When an object is travelling through the air, the force works in the opposite direction.

  • While a sports vehicle with a streamlined design will encounter reduced air resistance and experience less drag, the automobile will be able to move more quickly than a truck with a flat front.
  • The speed, area, and shape of the object passing through the air all affect air resistance. Air density and resistance are affected by altitude, temperature, and humidity. The resistance increases with speed and area, respectively.

Learn more about Air resistance here:

brainly.com/question/27965545

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5 0
2 years ago
A solid conducting sphere with radius RR that carries positive charge QQ is concentric with a very thin insulating shell of radi
svetlana [45]

Answer:

E=0 at r < R;

E=\frac{1}{4\pi\epsilon}\frac{Q}{r^{2}} at 2R > r > R;

E=\frac{1}{4\pi\epsilon} \frac{2Q}{r^{2}} at r >= 2R

Explanation:

Since we have a spherically symmetric system of charged bodies, the best approach is to use Guass' Theorem which is given by,

\int {E} \, dA=\frac{Q_{enclosed}}{\epsilon} (integral over a closed surface)

where,

E = Electric field

Q_{enclosed} = charged enclosed within the closed surface

\epsilon = permittivity of free space

Now, looking at the system we can say that a sphere(concentric with the conducting and non-conducting spheres) would be the best choice of a Gaussian surface. Let the radius of the sphere be r .

at r < R,

Q_{enclosed} = 0 and hence E = 0 (since the sphere is conducting, all the charges get repelled towards the surface)

at 2R > r > R,

Q_{enclosed} = Q,

therefore,

E\times4\pi r^{2}=\frac{Q_{enclosed}}{\epsilon}      

(Since the system is spherically symmetric, E is constant at any given r and so we have taken it out of the integral. Also, the surface integral of a sphere gives us the area of a sphere which is equal to 4\pi r^{2})

or, E=\frac{1}{4\pi\epsilon}\frac{Q}{r^{2}}

at r >= 2R

Q_{enclosed} = 2Q

Hence, by similar calculations, we get,

E=\frac{1}{4\pi\epsilon} \frac{2Q}{r^{2}}

4 0
4 years ago
A 33.0 g iron rod, initially at 22.7 ∘c, is submerged into an unknown mass of water at 63.3 ∘c, in an insulated container. the f
professor190 [17]
When the iron and the water reach thermal equilibrium, they have same temperature, T=58.5^{\circ}C.
We can consider this as an isolated system, so the heat released by the water is equal to the heat absorbed by the iron.

The hear released by the water is:
Q_w =m_w C_{sw} \Delta T_w
where m_w is the water mass, C_{sw}=4.186 J/(g^{\circ}C) is the specific heat of the water, and \Delta T_w = 63.6^{\circ}-58.5^{\circ}=5.1^{\circ}C is the variation of temperature of the water.

Similarly, the heat absorbed by the iron is:
Q_i = m_i C_{si} \Delta T_i
where m_i = 33.0 g is the iron mass, C_{si}=0.444 J/(g^{\circ}C) is the iron specific heat, and \Delta T_i = 58.5^{\circ}-22.7^{\circ}=35.8^{\circ}C is the variation of temperature of the iron.

Writing Q_w=Q_i and replacing the numbers, we can solve to find mw, the mass of the water:
m_w= \frac{m_i C_{si} \Delta T_i}{C_{sw} \Delta T_w} =24.6 g
4 0
3 years ago
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