Answer:
net force would be 50 N right
Explanation:
Usually describes a system by a set of variables in a set of equations established relationships between the variables and variables maybe of many types real or integer numbers Boolean values of strings for example
Surface area and Mass
When a leaf falls, it is being accelerated by gravity to the ground but opposed by air resistance also the drag. The net force on a leaf will therefore be calculated by subtracting its weight of the leaf from its drag.
<h3>What is Air resistance ?</h3>
Air exerts a force known as air resistance. When an object is travelling through the air, the force works in the opposite direction.
- While a sports vehicle with a streamlined design will encounter reduced air resistance and experience less drag, the automobile will be able to move more quickly than a truck with a flat front.
- The speed, area, and shape of the object passing through the air all affect air resistance. Air density and resistance are affected by altitude, temperature, and humidity. The resistance increases with speed and area, respectively.
Learn more about Air resistance here:
brainly.com/question/27965545
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Answer:
at r < R;
at 2R > r > R;
at r >= 2R
Explanation:
Since we have a spherically symmetric system of charged bodies, the best approach is to use Guass' Theorem which is given by,
(integral over a closed surface)
where,
= Electric field
= charged enclosed within the closed surface
= permittivity of free space
Now, looking at the system we can say that a sphere(concentric with the conducting and non-conducting spheres) would be the best choice of a Gaussian surface. Let the radius of the sphere be r .
at r < R,
= 0 and hence
= 0 (since the sphere is conducting, all the charges get repelled towards the surface)
at 2R > r > R,
= Q,
therefore,
(Since the system is spherically symmetric, E is constant at any given r and so we have taken it out of the integral. Also, the surface integral of a sphere gives us the area of a sphere which is equal to
)
or, 
at r >= 2R
= 2Q
Hence, by similar calculations, we get,

When the iron and the water reach thermal equilibrium, they have same temperature,

.
We can consider this as an isolated system, so the heat released by the water is equal to the heat absorbed by the iron.
The hear released by the water is:

where

is the water mass,

is the specific heat of the water, and

is the variation of temperature of the water.
Similarly, the heat absorbed by the iron is:

where

is the iron mass,

is the iron specific heat, and

is the variation of temperature of the iron.
Writing

and replacing the numbers, we can solve to find mw, the mass of the water: