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bazaltina [42]
3 years ago
13

What does gravitational potential energy typically change into? Question 8 options: A-Electric energy B- Kinetic energy C- Radio

active energy D-Radioactive energy
Physics
2 answers:
MariettaO [177]3 years ago
7 0
The answer is “B”, Kinetic Energy
nika2105 [10]3 years ago
6 0

<em>Answer:</em>

<em>kinetic energy </em>

<em>Explanation:</em>

<em>i should know i had a test about it.</em>

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How much work is required to carry an electron from positive terminal of 12Volt battery to negative terminal?
Oliga [24]

Answer:

Explanation:

Work required = q x V

where q is charge on electron and V is potential difference

= 1.6 x 10⁻¹⁹  x 12

= 19.2 x 10⁻¹⁹ J

4 0
3 years ago
Find the final velocity of a 40 kg skateboarder traveling at an initial velocity of 10 m/s that moves up a hill from a height of
slavikrds [6]

Answer:

vf = 0

Explanation:

Since the initial height hi = 0, we can rewrite the energy equation as

vf^2 = vi^2 - 2ghf = (10 m/s)^2 - 2(10 m/s^2)(5 m) = 0

Therefore, his final velocity vf is

vf = 0

3 0
3 years ago
What was the hikers average velocity during part D of the hikes?
pychu [463]
Velocity = displacement / time
v = 6 / 3/4
v = 6*4/3
v = 24/3
v = 8 m/s toward north

In short, Your Answer would be 8 m/s north

Hope this helps!
8 0
3 years ago
Read 2 more answers
Convert 60 km/ hr into m/s
elixir [45]

Answer:

1 KM per minute is the real speed in minutes, turn that into 1000 meters per minute and divided by 60, you get a good number of 16.6666666667 which means you could go 50 meters per 3 seconds

Explanation:

so it would be 16.6666666667 meters per second

4 0
3 years ago
The pupil of a cat's eye narrows to a slit width of 0.5 mm in daylight. What is the angular resolution of the cat's eye in dayli
Elenna [48]

Answer:

C. 10⁻³ rads

Explanation:

Here, we shall use Rayleigh's Criterion to find out the angular resolution of Cat's eye during day light. Rayleigh's Criterion is written as follows:

θ = λ/a

where,

θ = angular resolution of Cat's eye = ?

λ = wavelength = 500 nm = 5 x 10⁻⁷ m

a = slit width of eye = 0.5 mm = 5 x 10⁻⁴ m

Therefore,

θ = (5 x 10⁻⁷ m/5 x 10⁻⁴ m)

Therefore,

θ = 0.001

θ = Sin⁻¹(0.001)

θ = 0.001 rad = 1 x 10⁻³ rad

Hence, the correct answer is:

<u>C. 10⁻³ rads</u>

4 0
3 years ago
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