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Elanso [62]
2 years ago
13

What is the full form of alcl3​

Chemistry
1 answer:
Likurg_2 [28]2 years ago
8 0

Answer:

Aluminum Chloride

Explanation:

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How do flowering plants depend on other living things in order to reproduce?
Rufina [12.5K]

Answer:

They depend on people to water them and make sure they are by a window for sunlight

Explanation:

plants cant do these things by themselves

5 0
2 years ago
Read 2 more answers
Which criteria determine whether a heterogeneous mixture is a colloid or a suspension
Artemon [7]
<span>whether the particles do not settle for an extended period of time</span>
6 0
2 years ago
A sample of argon has a volume of 1.2 L at STP. If the temperature is increased to 21 c and the pressure is lowered to 0.80 atm,
Nuetrik [128]

Answer:

The new volume is 1.62 L

Explanation:

Boyle's law says:

"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure." It is expressed mathematically as:

Pressure * Volume = constant

o P * V = k

Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T}=k

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. So this law indicates that the quotient between pressure and temperature is constant.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T}=k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law.

\frac{P*V}{T}=k

Having an initial state 1 and a final state 2 it is possible to say that:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

Standard temperature and pressure (STP) indicate pressure conditions P = 1 atm and temperature T = 0 ° C = 273 ° K. Then:

  • P1= 1 atm
  • V1= 1.2 L
  • T1= 273 °K
  • P2= 0.80 atm
  • V2= ?
  • T2= 21°C= 294 °K

Replacing:

\frac{1 atm* 1.2 L}{273K} =\frac{0.8 atm*V2}{294K}

Solving:

V2=\frac{1 atm*1.2 L}{273 K} *\frac{294 K}{0.8 atm}

V2= 1.62 L

<u><em>The new volume is 1.62 L</em></u>

<u><em></em></u>

8 0
2 years ago
Convert 300 kelvin to degree Celsius​
Jlenok [28]

Answer: 26.85 degrees

Explanation:

5 0
3 years ago
Given the following data in the Determination of Molar Mass of CO2 lab : Mass (before rxn): test tube HCl(aq) stir bar capsule 2
RSB [31]

Answer:

.259 g

Explanation:

PV = nRT

n = PV / RT

= .986 x 0.144 / .082 x 293.6

= .005897 moles

= .005897 x 44 g

= .259 g

3 0
2 years ago
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