The mass in grams of the given beryllium sulfide is 99.2 g. The correct option is the second option - 99.2 g BeS
<h3>Calculating mass of a compound </h3>
From the question, we are to determine the mass of the given beryllium sulfide.
From the given information,
Number of moles of beryllium sulfide (BeS) given = 2.42 moles
Using the formula,
Mass = Number of moles × Molar mass
Molar mass of BeS = 41 g/mol
Then,
Mass of BeS = 2.42 × 41
Mass of BeS = 99.22
Mass of BeS ≅ 99.2 g
Hence, the mass in grams of the given beryllium sulfide is 99.2 g. The correct option is the second option - 99.2 g BeS
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Answer:
The biological sample that pregnancy tests use to detect pregnancy is urine
You are given the neutralization of acetic acid with sodium hydroxide. Also, you are given the k for acetic acid, which is 1.8 x 10⁻⁵. You are asked to find the<span> approximate value of the equilibrium constant, kn, for the neutralization. We will have a reaction of both acetic acid and sodium hydroxide.
CH</span>₃COOH + NaOH → CH₃COONa + H₂O
which comes from
CH₃COOH → CH₃COO⁻ + H⁺
H⁺ + OH⁻ → H₂O<span>
</span>The k for water is always 1.0 x 10¹⁴. The Ksp for the reaction will be
<span>
Ksp = [</span>CH₃COOH][H₂O]
Ksp = (1.8 x 10⁻⁵)(1.0 x 10¹⁴)
<span>Ksp = 1.8 x 10</span>⁹
Answer:
The α-ketoglutarate dehydrogenase enzyme is structurally and functionally homologous to the pyruvate dehydrogenase complex.
hope it helps
According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.
<h3>What is IUPAC convention?</h3>
IUPAC convention of organic chemistry is a method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).
The name of the compound is written out with the substituents in alphabetical order followed by the base name (derived from the number of carbons in the parent chain).
Types of IUPAC Nomenclature of a few important aliphatic compounds:
- Alkane
- Alkene
- Alkyne
Example :
Ethane, which has 2 carbon atoms and 6 hydrogen atoms, with the molecular formula of = C₂H₆
Formation of alkyl group:
Methane (CH₄) Remove 1 hydrogen (H) convert to methyl (H₃-C-)
Example: Propyl (-CH₃ - CH₂ - CH₂ - )
According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.
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