Answer:
1-46
2-18
Explanation:
c=12 H=1 O=16
ethanol (12×2)+(6×1)+(16)=46
water (2×1)+(16)=18
The Nernst equation allows us to predict the cell potential for voltaic cells under conditions other than the standard conditions of 1M, 1 atm, 25°C. The effects of different temperatures and concentrations may be tracked in terms of the Gibbs energy change ΔG. This free energy change depends upon the temperature & concentrations according to ΔG = ΔG° + RTInQ where ΔG° is the free energy change under conditions and Q is the thermodynamic reaction quotient. The free energy change is related to the cell potential Ecell by ΔG= nFEcell
so for non-standard conditions
-nFEcell = -nFE°cell + RT InQ
or
Ecell = E°cell - RT/nF (InQ)
which is called Nernst equation.
Molar mass of oxygen is:
M(O)=16 g/mol
Molar mass of carbon is:
M(C)=12 g/mol
Molar mass of carbon dioxide is:
M(CO2)=M(C)+2*M(O)
M(CO2)=12 g/mol+2*16g/mol
M(CO2)=44 g/mol
<span>Molar mass(M) is the mass of 1 mole of the substance (grams per mole of a compound).</span>
The acids found in alcohol that make it evaporate are called organic acids.
An organic acid is an organic compound that has acidic properties. There are two types: one has a carboxyl (COOH) group, and the other type has a phenol group.
The most common organic acids are those with a carboxyl group and include acetic acid, formic acid, lactic acid and all fatty acids. Perfumes include organic acid in their composition to make them volatile. Volatile substances evaporate easily, and this is important for perfumes. They need to dissipate easily into the surrounding environment and spread their good smell.
Answer:
the energy of the third excited rotational state 
Explanation:
Given that :
hydrogen chloride (HCl) molecule has an intermolecular separation of 127 pm
Assume the atomic isotopes that make up the molecule are hydrogen-1 (protium) and chlorine-35.
Thus; the reduced mass μ = 
μ = 
μ = 
∵ 1 μ = 1.66 × 10⁻²⁷ kg
μ = 
μ = 1.6139 × 10⁻²⁷ kg
The rotational level Energy can be expressed by the equation:
where ;
J = 3 ( i.e third excited state) &
We know that :
1 J = 
