1) The frequency of the sound is
while the speed of sound is
So we can use the relationship between wavelength, speed and frequency of a wave to find the wavelength corresponding to this sound:
2) The wavelength in this case is
while the frequency of the wave is
So we can use the same relationship we used in part 1) to find the speed of the sound wave:
3) The velocity of the wave is
while its wavelength is
therefore we can find its frequency by using the usual relationship:
Answer:
Diagram A
Explanation:
When an object is travelling in a circular path it has an acceleration called centripetal acceleration, even if it is moving with uniform speed. This acceleration is attributed to the object due to change in the direction of velocity at every instant during the motion.
The direction of the velocity of the object is tangent to the circular path at every instant and if the object beaks free of the circular motion, such as breaking of the string, then it will go in the direction tangent to the circle at that instant. Hence, the diagram that best shows the direction ball will travel is:
<u>Diagram A</u>
Answer:
7,272.7m
Explanation:
Our knowns:
a = 5.2m/s^2
t = 32.8s
= 0 m/s
Our Unknowns:
Distance (x): ?
We can use displacement formula:
ΔX = t + a
Plug in knowns:
X = 0 + 1/2 ((5.2)(32.8))^2
Answer:
ΔX = 7272.7m
(I beleive this should be right) let me know if it helped!
Answer:
Part a)
m = 232.1 gram
Part b)
M = 928.6 gram
Explanation:
Part a)
As we know that frequency of vibration for a given spring block system is given by formula
so if it is given as 0.90 Hz then we will have
Now if additional mass is attached with it the frequency changed to 0.50 Hz
now divide two equations
Part b)
Now the frequency is changed to 0.45 Hz
so again we will have
again divide it with first equation above
as we know that m = 232.1 g
so total mass needed for 0.45 Hz will be
Answer:
0.33m/s²
Explanation:
Given parameters:
Initial velocity = 19.9m/s
Final velocity = 4.4m/s
Time = 47.6s
Unknown:
Acceleration = ?
Solution:
To solve this problem, we use the expression below:
Acceleration =
v is the final velocity
u is the initial velocity
t is the time taken
Acceleration =
Acceleration = -0.33m/s²
This is a deceleration