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jekas [21]
3 years ago
8

Which type of work is a textile engineer most likely to do?

Engineering
1 answer:
pickupchik [31]3 years ago
7 0

Answer:

B because as a textile engineer, your job is to help design and create fabric, including the equipment and materials needed for fabrication.

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A ten-station transfer machine has an ideal cycle time of 30 sec. The frequency of line stops is 0.075 stops per cycle. When a l
goldfiish [28.3K]

Answer:

62.5%

Explanation:

We are given that

A ten-station transfer machine has ideal cycle time=30 sec=\frac{30}{60}=0.5 min

Frequency of line=0.075 stops per cycle

Average time=4 min

We have to determine the line efficiency

T_p=0.5+0.075(4)=0.5+0.3=0.8

Line efficiency=\frac{0.5}{0.8}\times 100=62.5%

Hence, the line efficiency=62.5%

8 0
4 years ago
The resultant force is directed along the positive x axis and has a magnitude of 1330 N.
Andrew [12]

Answer:

the magnitude of F_A is 752 N

the direction theta of F_A is 57.9°

Explanations:

Given that,

Resultant force = 1330 N in x direction

∑Fx = R

from the diagram of the question which i uploaded along with this answer

FB = 800 N

FAsin∅ + FBcos30 = 1330 N

FAsin∅ = 1330 - (800 × cos30)

FA = 637.18 / sin∅

Now ∑Fx = 0

FAcos∅ - FBsin30 = 0

we substitute for FA

(637.18 / sin∅)cos∅ = 800 × sin30

637.18 / 800 × sin30 = sin∅/cos∅

and we know that { sin∅/cos∅ = tan∅)

so tan∅ = 1.59295

∅ = 57.88° ≈ 57.9°

THEREFORE FROM THE EQUATION

FA = 637.18 / sin∅

we substitute ∅

so FA = 637.18 / sin57.88

FA = 752 N

3 0
3 years ago
Describe the make-up of an internal combustion engine.<br> Pls answer quickly.
Whitepunk [10]

Answer:

The engine consists of a fixed cylinder and a moving piston. The expanding combustion gases push the piston, which in turn rotates the crankshaft. Ultimately, through a system of gears in the power-train, this motion drives the vehicle's wheels.

Explanation:

8 0
3 years ago
A single lane highway has a horizontal curve. The curve has a super elevation of 4% and a design speed of 45 mph. The PC station
andreyandreev [35.5K]

Answer: 112 + 19.27

Explanation:

Super elevation is an inward transverse slope provided through out the length of the horizontal curve which ends up serving as a counteract to the centrifugal force and checks tendency of overturning. It changes from infinite radius to radius of a transition curve.

Super curve elevation (e) = 4%

4/100= 0.04

e= V^2/gR

Make R the subject of the formula.

egR= V^2

R= V^2/eg

V= 45mph

=45 × 0.44704m/s

=20.1168m/s

g (force due to gravity) =9.81

Therefore,

R= (20.1168)^2/9.81 × 0.04

= 1031.31m

Tangent Length( T) = PI - PC

Tangent Length= 10875 - 10500

=375m

T= R Tan(I/2)

375= 1031.31 × Tan(I/2)

I= 39.96

Also,

L= πRI/180

= 719.27m

Station PT= Stat PC+ L

10500 + 719.27

=11219.27

=112 + 19.27

6 0
3 years ago
Two technicians are discussing variable valve timing technician a says that changing the exhaust valve timing how to reduce exha
g100num [7]

Answer:

Both technicians A and B are correct.

Explanation:

Variable valve timing is the process of changing the time of a valve lift in the internal combustion engine. This process is usually used to enhance the performance,emissions or the efficient consumption of fuel.

Now a days, variable valve timing is commonly used with a combination of variable valve lift systems in internal combustion engines.

Therefore,  technician A(changing the exhaust valve timing how to reduce exhaust emissions) and technician B (it changes in the intake valve timing helped increase low speed torque) are correct.

3 0
3 years ago
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