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Leno4ka [110]
3 years ago
15

How can I use the flux density B formula if I don’t know magnetic flux

Engineering
1 answer:
BabaBlast [244]3 years ago
3 0

Answer:

use the dimensions shown in the figure

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Saturated water vapor undergoes a throttling process from 1bar to a 0.35bar. What is the change in temperature for this process?
mamaluj [8]

Answer:

-25.63°C.

Explanation:

We know that throttling is a constant enthalpy process

      h_1=h_2

From steal table

We know that if we know only one property in side the dome then we will find the other property by using steam property table.

  Temperature at saturation pressure 1 bar is 99.63°C and  Temperature at saturation pressure 0.35 bar is about 74°C .

So from above we can say that change in temperature is -25.63°C.

But there is no any option for that .

4 0
3 years ago
An electric motor is to be supported by four identical mounts. Each mount can be treated as a linear prevent problems due requir
Artyom0805 [142]

GIVEN:

Amplitude, A = 0.1mm

Force, F =1 N

mass of motor, m = 120 kg

operating speed, N = 720 rpm

\frac{A}{F} =  \frac{0.1\times 10^{-3}}{1} = 0.1\times 10^{-3}

Formula Used:

A = \frac{F}{\sqrt{(K_{t} - m\omega ^{2}) +(\zeta \omega ^{2})}}

Solution:

Let Stiffness be denoted by 'K' for each mounting, then for 4 mountings it is 4K

We know that:

\omega = \frac{2 \pi\times N}{60}

so,

\omega = \frac{2 \pi\times 720}{60} = 75.39 rad/s

Using the given formula:

Damping is negligible, so, \zeta = 0

\frac{A}{F} will give the tranfer function

Therefore,

\frac{A}{F} = \frac{1}{\sqrt{(4K - 120\ ^{2})}}

0.1\times 10^{-3} =  \frac{1}{\sqrt{(4K - 120\ ^{2})}}

Required stiffness coefficient, K = 173009 N/m = 173.01 N/mm

8 0
3 years ago
How is TEL (total equivalent length) measured and calculated? .​
ollegr [7]
Measure the longest circuit and add 50% for fittings and terminal units.
3 0
3 years ago
The mathematical relationship between
11Alexandr11 [23.1K]
4) Ohms law thats the answer
7 0
3 years ago
Match the following items with their correct description.
Lera25 [3.4K]

Answer:

A. Manufacturers rating capacity ↔  3. Must be marked on all jacks; must not be exceeded

B. Block Used to lift and hold heavy loads, allow them for travel ↔ 1. Place the jack head against this

C. Level surface ↔ 4. Place this under the base of the jack when it's necessary to provide a firm foundation

D. Jack ↔ 2. Used to lift and hold heavy loads, allow them for travel

Explanation:

The manufacturers rating for a jack is labelled on all jacks and should be referenced to compare with the load to be lifted so as to ensure a safe and successful lifting.

In order to lift a load, such as a car, it is required to place the jack on a level surface to provide balance during the lifting task

The head of the jack is placed against the block for lifting heavy objects for proper performance

8 0
3 years ago
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