A teacher has 16 paper clips in one box and 48 paper clips in another box the teacher separates all of the paper clips into 8 eq
2 answers:
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Ok so for slope it's difference in y dividing by the difference of x. The difference of y is 10 - 6 which is 4, and the change in x is 5 - (-3) which is 8. Dividing 4 by 8 gets us 1/2. So the slope is 1/2. Slope intercept form would be y = mx + b, and the slope is 1/2 so it'd be y = (1/2)x + b. Plug in a point and you get b = 15/2. So the final slope intercept form would be y = (1/2)x + 15/2. For point slope form just put in a point and slope and you get y - 6 = (1/2) × (x + 3). Standard form would have to be arranged from slope intercept. So multiplying 2 to the slope intercept form we get 2y = x + 15. Subtracting x we get -x + 2y = 15. In standard form we don't want x to be negative so just multiply by negative one and we get x - 2y = -15.
V1=(-2,4)=(x1,y1)→x1=-2, y1=4
V2=(4,0)=(x2,y2)→x2=4, y2=0
V3=(2,-3)=(x3,y3)→x3=2, y3=-3
V4=(x4,y4)→x4=?, y4=?
V1-V2
dx=x2-x1=4-(-2)=4+2→dx=6
dy=y2-y1=0-4→dy=-4
V4-V3
dx=x3-x4→6=2-x4
Solving for x4:
6=2-x4→6-2=2-x4-2→4=-x4→(-1)(4=-x4)→-4=x4→x4=-4
dy=y3-y4→-4=-3-y4
Solving for y4:
-4=-3-y4→-4+3=-3-y4+3→-1=-y4→(-1)(-1=-y4)→1=y4→y4=1
V4=(x4, y4)→V4=(-4, 1)
Answer: The coordinates of the fourth vertex are (-4,1)
V2=(4,0)=(x2,y2)→x2=4, y2=0
V3=(2,-3)=(x3,y3)→x3=2, y3=-3
V4=(x4,y4)→x4=?, y4=?
V1-V2
dx=x2-x1=4-(-2)=4+2→dx=6
dy=y2-y1=0-4→dy=-4
V4-V3
dx=x3-x4→6=2-x4
Solving for x4:
6=2-x4→6-2=2-x4-2→4=-x4→(-1)(4=-x4)→-4=x4→x4=-4
dy=y3-y4→-4=-3-y4
Solving for y4:
-4=-3-y4→-4+3=-3-y4+3→-1=-y4→(-1)(-1=-y4)→1=y4→y4=1
V4=(x4, y4)→V4=(-4, 1)
Answer: The coordinates of the fourth vertex are (-4,1)