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zaharov [31]
3 years ago
15

10 POINTS!! SPACE QUESTION!!

Physics
2 answers:
wlad13 [49]3 years ago
5 0
The First one trust...
Damm [24]3 years ago
4 0

Answer: A (first option)

Explanation: In general, the surface temperatures decreases with increasing distance from the sun. Any warm object in space loses heat via infrared radiation; also visible radiation if it is hot enough. The hotter is the object, the faster it loses heat. Consequently any object warmed by the Sun stays at equilibrium temperature - it warms up until the radiative heat loss equals to the heat received, and cannot get any warmer beyond that.

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Two 84.5 g ice cubes are dropped into 30 g of water in a glass. If the water is initially at a temperature of 50 C and if the ic
Setler [38]

Answer:

final temperature will be 0 degree C

Total amount of ice will be

m_{ice} = 182 g

total amount of water

m_{water} = 17 g

Explanation:

After thermal equilibrium is achieved we can say that

Heat given by water = heat absorbed by ice cubes

so we will have

Heat given by water to reach 0 degree C

Q_1 = m_1s_1 \Delta T_1

Q_1 = 0.030(4186)(50 - 0)

Q_1 = 6279 J

heat absorbed by ice cubes to reach 0 degree

Q_2 = m_2 s_2 \Delta T_2

Q_2 = (0.169)(2100)(30)

Q_2 = 10647 J

so we will have

Q_2 > Q_1

so here we can say that few amount of water will freeze here to balance the heat

10647 - 6279 = mL

m = \frac{10647 - 6279}{335000}

m = 13 g

so final temperature will be 0 degree C

Total amount of ice will be

m_{ice} = 84.5 + 84.5 + 13

m_{ice} = 182 g

total amount of water

m_{water} = 30 - 13

m_{water} = 17 g

4 0
3 years ago
A technician is checking refrigerant system pressures. Both high- and low-side service ports are located on the A/C compressor.
konstantin123 [22]

Answer:

Two major causes are outline bellow

1. The presence of air in the system

2. Clogged condenser

Explanation:

1. The presence of air in the system

One of the causes that have been established in relation to high compressor discharge pressure is the presence of air in the system. When this takes place, your best solution is to recharge the system.

2. Clogged condenser

Another is a clogged condenser in which case you will need to clean the condenser so that it will function properly. When you happen to spot that the discharge valve is closed and it is causing high discharge pressure on the compressor, you can solve that easily by opening the valve

5 0
3 years ago
P6: An object of mass m sits on a spring of constant k in an elevator that is accelerating upwards with acceleration a. a) In te
tankabanditka [31]

Answer:

(a). The spring compressed is \dfrac{ma+mg}{k}.

(b). The acceleration is 1.5 g.

Explanation:

Given that,

Acceleration = a

mass = m

spring constant = k

(a). We need to calculate the spring compressed

Using balance equation

kx-mg=ma

x=\dfrac{ma+mg}{k}....(I)

The spring compressed is \dfrac{ma+mg}{k}.

(b). If the compression is 2.5 times larger than it is when the mass sits in a still elevator,

The compression is given by

x=2.5\times x_{0}

Here, acceleration is zero

So, x=2.5\times\dfrac{mg}{k}

We need to calculate the acceleration

Put the value of x in equation (I)

2.5\times \dfrac{mg}{k}=\dfrac{ma+mg}{k}

2.5\times\dfrac{mg}{k}=\dfrac{m}{k}(a+g)

a=2.5g-g

a=1.5g

Hence, (a). The spring compressed is \dfrac{ma+mg}{k}.

(b). The acceleration is 1.5 g.

8 0
3 years ago
Which of the following examples does not make use of total internal reflection?
liubo4ka [24]

Answer:

laser pointer does not make use of total internal reflection

7 0
3 years ago
A high power line carries a current of 1.0 kA. What is the strength of the magnetic field this line produces at the ground, 10 m
solmaris [256]

Answer:

The strength of the magnetic field that the line produces is 2x10^{-5} Tesla.

Explanation:

From Biot-Savart law, the equation to determine the strength of the magnetic field for any straight wire can be deduced:

           

B = \frac{\mu_{0}I}{2\pi r} (1)      

                                     

Where \mu_{0} is the permiability constant, I is the current and r is the distance from the wire.    

             

Notice that it is necessary to express the current, I, from kiloampere to ampere.

I = 1.0kA \cdot \frac{1000A}{1kA} ⇒ 1000A

Finally, equation 1 can be used:

B = \frac{(4\pi x10^{-7}T.m/A)(1000A)}{2\pi (10m)}    

           

B = 2x10^{-5}T    

Hence, the strength of the magnetic field that the line produces is 2x10^{-5} Tesla.

         

8 0
3 years ago
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