<h3>Question:</h3>
How to find g (acceleration due to gravity)
<h3>Solution:</h3>
We know,
Acceleration due to gravity (g)
where, G = Gravitational constant
M = Mass of the earth
R = Radius of the earth
Putting these values of G, M and R in the above formula, we get
So, the value of acceleration due to gravity is
Hope it helps.
Do comment if you have any query.
Answer:
1.029
Explanation:
1.0090 can also be looked at as "1.009"
0.02 can also be looked at as "0.020"
I think of it as 20+9 which is 29. There for your answer should be 1.029. There are no measurement rules applying to this equation since they are both in centimeters. So you don't have to convert anything.
An object with non-zero mass (even negligible mass is non-zero) will never reach the speed of light. Due to relativistic effects, each "unit" of acceleration becomes less effective at increasing your velocity (relative to some other object, of course) as your relative velocity approaches the speed of light.
And even if there was a way, If you would accelerate to the 99,99% of the speed light in just 1 second, you would experience a G-force of aprox. 30,600,000 g's which is enough to kill you in a few seconds
Answer:
(A) Pepsin
Explanation:
From the graph it is clear that pepsin is the only enzyme which works in highly acidic condintion in the digestive system.
- less than 7 the liquid is acidic
- above 7 the liquid is basic
- at 7 the liquid is neutral
It has an optimum pH of about 1.5 at which its activity level is 8.5 as shown in graph.
Answer:
The rate of heat conduction through the layer of still air is 517.4 W
Explanation:
Given:
Thickness of the still air layer (L) = 1 mm
Area of the still air = 1 m
Temperature of the still air ( T) = 20°C
Thermal conductivity of still air (K) at 20°C = 25.87mW/mK
Rate of heat conduction (Q) = ?
To determine the rate of heat conduction through the still air, we apply the formula below.
Q = 517.4 W
Therefore, the rate of heat conduction through the layer of still air is 517.4 W
