<span>A free body diagram is a representation of how the forces that are acting on a point or particle interact. You place your point at the origin and then draw your forces.
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Answer:
As we are converting 220V AC into a 5V DC, first we need a step-down transformer to reduce such high voltage. Here we have used 9-0-9 1A step-down transformer, which convert 220V AC to 9V AC. In transformer there are primary and secondary coils which step up or step down the voltage according to the no of turn in the coils.
Selection of proper transformer is very important. Current rating depends upon the Current requirement of Load circuit (circuit which will use the generate DC). The voltage rating should be more than the required voltage. Means if we need 5V DC, transformer should at least have a rating of 7V, because voltage regulator IC 7805 at least need 2V more i.e. 7V to provide a 5V voltage.
Answer: Chilling with my homies
Chicken wings, Chicken wings
Hotdog and baloney
Chicken and macaroni
Chillin' wit mah homiiieees
Chicken wing chicken wing
Hot dogs and balogna
Chicken and macaroni
Chilling with mah Chilling with mah
Chicken chicken wing chicken chicken wing
Chicken chicken chicken chicken chicken wing
Chicken chicken chicken chicken wing
Chicken wings, Chicken wings
Hotdog and baloney
Chicken and macaroni
Chillin' wit mah homiiieees
Chicken wings, Chicken wings
Hotdog and baloney
Chicken and macaroni
Chillin' wit mah homiiieees homiiieeees
Chicken wings, Chicken wings
Hotdog and baloney
Chicken and macaroni
Chillin' wit mah homiiieees
Chillin' wit mah
Explanation:
im sorry i had to do it now pls give me brainliest thank u and have a blessed day:)
We will define the Total mass to calculate the force, so our values are:
Total Mass 
The Weight is,
Through the hook's Law we calculate X.
, where x is the lenght of compression and K the Spring constant.
We don't have a K-Spring, but we can assume a random value (or simply let the equation in function of K)
I assume a value of 
Answer:
angle minimum θ = 41.3º
Explanation:
For this exercise let's use Newton's second law in the condition of static equilibrium
N - W = 0
N = W
The rotational equilibrium condition, where we place the axis of rotation on the wall
We assume that counterclockwise rotations are positive
fr (l sin θ) - N (l cos θ) + W (l/2 cos θ) = 0
the friction force formula is
fr = μ N
fr = μ W
we substitute
μ m g l sin θ - m g l cos θ + mg l /2 cos θ = 0
μ sin θ - cos θ + ½ cos θ= 0
μ sin θ - ½ cos θ = 0
sin θ / cos θ = 1/2 μ
tan θ = 1/2 μ
θ = tan⁻¹ (1 / 2μ)
θ = tan⁻¹ (1 (2 0.57))
θ = 41.3º
